我正在创建一个试图从外键访问值的数据库.我创建了两个下表
CREATE TABLE Component(
ComponentID varchar2(9) PRIMARY KEY,TypeID varchar2(9) REFERENCES TypeComponent(TypeComponentID)
)
INSERT INTO Component VALUES(192359823,785404309)
INSERT INTO Component VALUES(192359347,785404574)
INSERT INTO Component VALUES(192359467,785404769)
INSERT INTO Component VALUES(192359845,785404867)
INSERT INTO Component VALUES(192359303,785404201)
INSERT INTO Component VALUES(192359942,785404675)
CREATE TABLE TypeComponent (
TypeComponentID varchar2(9) PRIMARY KEY,Type_Description varchar2(30) CONSTRAINT Type_Description
CHECK(Type_Description IN('Strap','Buckle','Stud')) NOT NULL
)
INSERT INTO TypeComponent VALUES(785404309,'Strap')
INSERT INTO TypeComponent VALUES(785404574,'Stud')
INSERT INTO TypeComponent VALUES(785404769,'Buckle')
INSERT INTO TypeComponent VALUES(785404867,'Strap')
INSERT INTO TypeComponent VALUES(785404201,'Buckle')
INSERT INTO TypeComponent VALUES(785404675,'Stud')
这是两个表. Component和TypeComponent. Component是TypeComponent的父实体,我试图运行以下INSERT语句：
INSERT INTO Component VALUES(192359823,785404309)
但它给了我错误
这是我在Oracle sql dev中到目前为止的会话
解决方法
首先尝试在TypeComponent表中插入,然后插入到Component表中.
根据错误：
ORA-02291:integrity constraint (string.string) violated – parent key not found
Cause:A foreign key value has no matching primary key value.
Action:Delete the foreign key or add a matching primary key.
这意味着您引用的表中没有匹配的键.
编辑#1
有关您的信息,请访问以下网站,您可以从中获得有关所有Oracle错误代码的帮助.
HTTP：// [ORA-02291] .ORA-code.com /
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