我真的需要一个简单求和的表上的计算列.
请看下面:
SELECT key3,SUM(UTOTALWBUD) FROM CONTACT1 INNER JOIN CONTACT2 ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO WHERE KEY1 = 'Client' GROUP BY KEY3
ALTER TABLE ManagerTaLog ADD WeeklyBudget as ( SELECT key3,SUM(UTOTALWBUD) FROM CONTACT1 JOIN CONTACT2 ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO WHERE KEY1 = 'Client' GROUP BY KEY3)
我收到了错误消息:
Msg 1046,Level 15,State 1,Line 4
Subqueries are not allowed in this context. Only scalar expressions are allowed.
请告知我该怎么办.
非常感谢
第2部分
我创造了一个功能;但是,我得到空值,请指教.
CREATE FUNCTION [dbo].[SumIt](@Key3 varchar) RETURNS TABLE AS RETURN ( SELECT SUM(UTOTALWBUD) FROM CONTACT1 JOIN CONTACT2 ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO JOIN Phone_List ON CONTACT1.KEY3 = Phone_List.[Manager ] WHERE KEY1 = 'Client' AND Phone_List.[Manager ] = @Key3 GROUP BY [Manager ] ) END GO
只需选择返回我想要添加到Phone_list表的值的语句
SELECT [Manager ],SUM(UTOTALWBUD) FROM CONTACT1 JOIN CONTACT2 ON CONTACT1.ACCOUNTNO = CONTACT2.ACCOUNTNO JOIN Phone_List ON CONTACT1.KEY3 = Phone_List.[Manager ] WHERE KEY1 = 'Client' GROUP BY [Manager ]
表定义
CREATE TABLE [dbo].[CONTACT1]( [ACCOUNTNO] [varchar](20) NOT NULL,[COMPANY] [varchar](40) NULL,[CONTACT] [varchar](40) NULL,[LASTNAME] [varchar](15) NULL,[DEPARTMENT] [varchar](35) NULL,[TITLE] [varchar](35) NULL,[SECR] [varchar](20) NULL,[PHONE1] [varchar](25) NOT NULL,[PHONE2] [varchar](25) NULL,[PHONE3] [varchar](25) NULL,[FAX] [varchar](25) NULL,[EXT1] [varchar](6) NULL,[EXT2] [varchar](6) NULL,[EXT3] [varchar](6) NULL,[EXT4] [varchar](6) NULL,[ADDRESS1] [varchar](40) NULL,[ADDRESS2] [varchar](40) NULL,[ADDRESS3] [varchar](40) NULL,[CITY] [varchar](30) NULL,[STATE] [varchar](20) NULL,[ZIP] [varchar](10) NOT NULL,[COUNTRY] [varchar](20) NULL,[DEAR] [varchar](20) NULL,[SOURCE] [varchar](20) NULL,[KEY1] [varchar](20) NULL,[KEY2] [varchar](20) NULL,[KEY3] [varchar](20) NULL,[KEY4] [varchar](20) NULL,[KEY5] [varchar](20) NULL,[STATUS] [varchar](3) NOT NULL,[NOTES] [text] NULL,[MERGECODES] [varchar](20) NULL,[CREATEBY] [varchar](8) NULL,[CREATEON] [datetime] NULL,[CREATEAT] [varchar](5) NULL,[OWNER] [varchar](8) NOT NULL,[LASTUSER] [varchar](8) NULL,[LASTDATE] [datetime] NULL,[LASTTIME] [varchar](5) NULL,[U_COMPANY] [varchar](40) NOT NULL,[U_CONTACT] [varchar](40) NOT NULL,[U_LASTNAME] [varchar](15) NOT NULL,[U_CITY] [varchar](30) NOT NULL,[U_STATE] [varchar](20) NOT NULL,[U_COUNTRY] [varchar](20) NOT NULL,[U_KEY1] [varchar](20) NOT NULL,[U_KEY2] [varchar](20) NOT NULL,[U_KEY3] [varchar](20) NOT NULL,[U_KEY4] [varchar](20) NOT NULL,[U_KEY5] [varchar](20) NOT NULL,[recid] [varchar](15) NOT NULL ) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY] GO CREATE TABLE [dbo].[Phone_List]( [Manager ] [nvarchar](255) NULL,[SalesCode] [nvarchar](255) NULL,[Email] [nvarchar](255) NULL,[PayrollCode] [nvarchar](255) NULL,[Mobile] [nvarchar](255) NULL,[FName] [nchar](20) NULL,[idd] [tinyint] NULL,[OD] [varchar](20) NULL,[WeeklyBudget] AS ([dbo].[SumIt]([manager])) ) ON [PRIMARY]
解决方法
您可以将查询包装到这样的函数中(它可以返回一个值):
CREATE FUNCTION dbo.SumIt(@Key1 varchar(max)) returns float as begin return (select sum(UTOTALWBUD) from CONTACT1 inner join CONTACT2 on CONTACT1.ACCOUNTNO=CONTACT2.ACCOUNTNO where KEY1=@key1 group by KEY3) END
并使用此函数代替calc字段 – 如下所示:
alter table ManagerTaLog add WeeklyBudget as dbo.SumIt(Key1)
注意
select * from ManagerTaLog
您应该以这样的方式更改函数,即接受NOT varchar值,但接受NVARCHAR(255) – 与Manager列相同的类型.尝试一下.