我有这个表结构. YearPart,MonthPart和DatePart包含他们描述的内容… EX:2011,1,19(分别)
DECLARE @agenda AS TABLE ( PID INT IDENTITY(1,1) PRIMARY KEY,YearPart int,MonthPart int,DayPart int,lib_title nvarchar(200),[filename] nvarchar(255),Meta_value nvarchar(2000) )
使用此示例数据:
INSERT INTO @agenda VALUES (2010,12,4,'Test Record','','') INSERT INTO @agenda VALUES (2011,3,'Another Record','Fred Birthday','Work Day',6,'2nd Test Record','')
我想要的是一个这样的XML输出:
<root> <Year Year="2010"> <Month Month="12"> <Day Day="4"> <Item RecordName="Test Record" RecordID="1" /> </Day> </Month> </Year> <Year Year="2011"> <Month Month="1"> <Day Day="3"> <Item RecordName="Another Record" RecordID="2" /> <Item RecordName="Geoffrey Birthday" RecordID="3" /> </Day> <Day Day="4"> <Item RecordName="Work Day" RecordID="4" /> </Day> </Month> <Month Month="12"> <Day Day="6"> <Item RecordName="2nd Test Record" RecordID="5" /> </Day> </Month> </Year> </root>
到目前为止,我还没有得到嵌套正常工作.我通常结束分组(例如,我得到多个Year = 2011元素,当只应该有一个).
如果这不能完成,我可以随时在.NET网站上创建XML
解决方法
可以做到
select a1.YearPart as '@Year',( select MonthPart as '@Month',(select DayPart as '@Day',(select lib_title as '@RecordName',PID as '@RecordID' from @agenda as a4 where a4.DayPart = a3.DayPart and a4.MonthPart = a2.MonthPart and a4.YearPart = a1.YearPart for xml path('Item'),type ) from @agenda as a3 where a3.YearPart = a1.YearPart and a3.MonthPart = a2.MonthPart group by a3.DayPart for xml path('Day'),type ) from @agenda as a2 where a1.YearPart = a2.YearPart group by a2.MonthPart for xml path('Month'),type ) from @agenda as a1 group by YearPart for xml path('Year'),root