我有这个表结构. YearPart,MonthPart和DatePart包含他们描述的内容… EX：2011,1,19(分别)
DECLARE @agenda AS TABLE ( PID INT IDENTITY(1,1) PRIMARY KEY,YearPart int,MonthPart int,DayPart int,lib_title nvarchar(200),[filename] nvarchar(255),Meta_value nvarchar(2000) )
使用此示例数据：
INSERT INTO @agenda VALUES (2010,12,4,'Test Record','','') INSERT INTO @agenda VALUES (2011,3,'Another Record','Fred Birthday','Work Day',6,'2nd Test Record','')
我想要的是一个这样的XML输出：
<root>
<Year Year="2010">
<Month Month="12">
<Day Day="4">
<Item RecordName="Test Record" RecordID="1" />
</Day>
</Month>
</Year>
<Year Year="2011">
<Month Month="1">
<Day Day="3">
<Item RecordName="Another Record" RecordID="2" />
<Item RecordName="Geoffrey Birthday" RecordID="3" />
</Day>
<Day Day="4">
<Item RecordName="Work Day" RecordID="4" />
</Day>
</Month>
<Month Month="12">
<Day Day="6">
<Item RecordName="2nd Test Record" RecordID="5" />
</Day>
</Month>
</Year>
</root>
到目前为止,我还没有得到嵌套正常工作.我通常结束分组(例如,我得到多个Year = 2011元素,当只应该有一个).
如果这不能完成,我可以随时在.NET网站上创建XML
解决方法
可以做到
select
a1.YearPart as '@Year',( select MonthPart as '@Month',(select DayPart as '@Day',(select
lib_title as '@RecordName',PID as '@RecordID'
from @agenda as a4
where a4.DayPart = a3.DayPart and
a4.MonthPart = a2.MonthPart and
a4.YearPart = a1.YearPart
for xml path('Item'),type
)
from @agenda as a3
where a3.YearPart = a1.YearPart and
a3.MonthPart = a2.MonthPart
group by a3.DayPart
for xml path('Day'),type
)
from @agenda as a2
where a1.YearPart = a2.YearPart
group by a2.MonthPart
for xml path('Month'),type
)
from @agenda as a1
group by YearPart
for xml path('Year'),root
