SELECT * FROM transactions WHERE id NOT LIKE '1%' AND NOT LIKE '2%'
我觉得很傻,但我做错了什么？
SELECT * FROM transactions WHERE id NOT LIKE '1%' AND id NOT LIKE '2%'
where子句中的AND连接2个完整条件表达式,如id NOT LIKE’1％’,并且不能用于列出ID不是“的多个值.
