sql-server – 使用SQL CTE打印树

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架构如下:
  1. CREATE TABLE [Structure](
  2. [StructureId] [uniqueidentifier] NOT NULL,[SequenceNumber] [int] NOT NULL,-- order for siblings,unique per parent
  3. [ParentStructureId] [uniqueidentifier] NULL,CONSTRAINT [Structure_PK] PRIMARY KEY CLUSTERED
  4. (
  5. [StructureId] ASC
  6. )
  7. ) ON [PRIMARY]
  8.  
  9. ALTER TABLE [Structure] WITH CHECK ADD CONSTRAINT [Structure_FK1]
  10. FOREIGN KEY([ParentStructureId])
  11. REFERENCES [Structure] ([StructureId])

目前,我可以通过以下CTE获取所有逻辑数据,但我想以深度优先的方式直接打印它.

  1. WITH SCTE (StructureId,Level,Seq,ParentId)
  2. AS
  3. (
  4. SELECT StructureId,SequenceNumber,[ParentStructureId]
  5. FROM Structure
  6. WHERE [ParentStructureId] IS NULL
  7. AND StructureId = 'F6C5F016-1270-47C1-972F-349C32DFC92A'
  8.  
  9. UNION ALL
  10.  
  11. SELECT Structure.StructureId,Level + 1,ParentStructureId
  12. FROM Structure
  13. INNER JOIN SCTE ON SCTE.StructureId = Structure.ParentStructureId
  14. )
  15.  
  16. SELECT * FROM SCTE
  17. ORDER BY Level,ParentId,Seq

输出如下(此处截断):

  1. StructureId Level Seq ParentId
  2. F6C5F016-1270-47C1-972F-349C32DFC92A 0 0 NULL
  3. D2E34429-401A-4A49-9E18-E81CCA0FB417 1 0 F6C5F016-1270-47C1-972F-349C32DFC92A
  4. 0CC5E16C-9194-40CA-9F72-1CED2972D7CA 1 1 F6C5F016-1270-47C1-972F-349C32DFC92A
  5. 1ECD1D30-EB85-42B0-969F-75794343E3B4 1 2 F6C5F016-1270-47C1-972F-349C32DFC92A
  6. EEC3A981-B790-4600-8CD1-F15972CD9230 2 0 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  7. 4406F639-2F58-4918-A9EF-A4B0F379BEA0 2 1 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  8. FCAF7870-C606-4AA6-85EE-57B90B1B0CC3 2 2 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  9. 855DF5FB-1593-4E5B-8EF9-3770B45F89D6 2 3 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  10. 3D16DF32-C04F-49B4-B0D9-5BDC9104F810 2 4 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  11. A1084D00-0198-47D9-87E0-BB8234233F14 2 5 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  12. CE443C0D-376F-46EC-9914-32C6B7200DB1 2 6 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  13. 0DEA587D-4FCF-414C-AD71-FB00829F8082 2 7 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
  14. CC9FC8D3-254A-486B-8DC4-07E57627476C 2 0 1ECD1D30-EB85-42B0-969F-75794343E3B4
  15. 215565CC-501F-4850-B8AE-5466DA5E6854 2 1 1ECD1D30-EB85-42B0-969F-75794343E3B4
  16. D4E6C8E5-5ADD-4AD1-B59B-1A672F66888A 2 2 1ECD1D30-EB85-42B0-969F-75794343E3B4
  17. 796C65BF-4714-4DBF-A97A-2150DBE3098C 2 3 1ECD1D30-EB85-42B0-969F-75794343E3B4
  18. B39DEB9C-BE42-43B4-9C38-968399D7D1E2 2 4 1ECD1D30-EB85-42B0-969F-75794343E3B4
  19. 6C2F70C6-1DA0-4E1A-BBC1-D7FCAFE6AFEE 2 0 D2E34429-401A-4A49-9E18-E81CCA0FB417
  20. 75D7B43B-C971-46B4-BC42-58C3605ADD79 2 1 D2E34429-401A-4A49-9E18-E81CCA0FB417
  21. 0B5AAAA0-A69F-431E-86BA-148444D7B1E6 2 2 D2E34429-401A-4A49-9E18-E81CCA0FB417
  22. CB3CF66B-D83A-45E2-953A-6F0CEE094F5B 2 3 D2E34429-401A-4A49-9E18-E81CCA0FB417
  23. 1D5F69C3-F036-4667-BD75-A0DC1506DB6D 2 4 D2E34429-401A-4A49-9E18-E81CCA0FB417
  24. 71B894F7-B9FC-44DE-AEDB-E6FA026A6082 2 5 D2E34429-401A-4A49-9E18-E81CCA0FB417
  25. F1DFA1E1-013B-449C-9D9D-14C64E75D418 2 6 D2E34429-401A-4A49-9E18-E81CCA0FB417

正如您所看到的,结果是“广度优先”,这使得打印树像现在一样不可能.

是否有任何方法(可能有一种微不足道的方式,但我的sql技能非常差)以“树形打印友好”格式获得结果列表?

我知道我可以将结果转储到程序中并对输出进行编码,但作为练习,我更喜欢在sql本身中执行此操作.

谢谢

解决方法

评论后编辑.您可以将路径添加到节点,并对其进行排序:
  1. declare @t table (id int,parent int)
  2. insert @t (id,parent) values (1,null),(2,1),(3,2),(4,3),(5,(6,5)
  3.  
  4. ; with cte as (
  5. select id,parent,cast(RIGHT(REPLICATE('0',12) +
  6. CONVERT(varchar(12),id),12) as varchar(max)) Path
  7. from @t
  8. where parent is null
  9. union all
  10. select child.id,child.parent,parent.Path + RIGHT(REPLICATE('0',12) +
  11. CONVERT(varchar(12),child.id),12) as Path
  12. from @t child
  13. join cte parent
  14. on parent.id = child.parent
  15. )
  16. select *
  17. from cte
  18. order by
  19. Path

这将首先打印根,然后按顺序打印.如果您的id可能大于12位,请增加char(x)强制转换中的数字.

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