我想做这样的事情:
SELECT round(100*(col_a - col_b)/col_a,1) as Foo,Foo - col_c as Bar
FROM my_table
WHERE...;
但是,我得到一个错误,说Foo是未知的.由于Foo是从一堆其他列的某些计算得出的,所以我不想再为Bar重复该公式.任何解决方法?
@H_
301_9@
SELECT Foo,Foo - col_c as Bar
from (
SELECT round(100*(col_a - col_b)/col_a,col_c
FROM my_table
WHERE...
) t;