我有点卡住了.我想做一个用户角色关系数据透视表,我的查询到目前为止看起来像这样:
WITH PIVOT_DATA AS ( SELECT * FROM ( SELECT USERNAME,GRANTED_ROLE FROM DBA_USERS@DB_LINK U LEFT OUTER JOIN DBA_ROLE_PRIVS@DB_LINK R ON U.USERNAME = R.GRANTEE ) ) SELECT * FROM PIVOT_DATA PIVOT ( COUNT(GRANTED_ROLE) FOR GRANTED_ROLE IN('CONNECT') -- Just an example ) ORDER BY USERNAME ASC;
它工作得非常好并且完成了工作,但是我不想编写我想在pivot_in_clause中搜索的任何角色,因为我们得到了大量的这些,我不想每次检查是否有任何变化.
那么有没有办法在pivot_in_clause中编写SELECT?我亲自尝试过:
[...] PIVOT ( COUNT(GRANTED_ROLE) FOR GRANTED_ROLE IN( SELECT ROLE FROM DBA_ROLES@DB_LINK ) ) [...]
但它总是在整个查询的第1行给我一个ORA-00936:“缺少表达式”,我不知道为什么.在pivot_in_clause中不能有SELECT或者我做错了吗?
解决方法@H_301_14@
您可以在脚本中构建动态查询,
看看这个例子:
variable rr refcursor
declare
bb varchar2(4000);
cc varchar2( 30000 );
begin
WITH PIVOT_DATA AS (
SELECT *
FROM
(
SELECT USERNAME,GRANTED_ROLE
FROM DBA_USERS U LEFT OUTER JOIN DBA_ROLE_PRIVS R
ON U.USERNAME = R.GRANTEE
)
)
select ''''|| listagg( granted_role,''',''' )
within group( order by granted_role ) || '''' as x
into bb
from (
select distinct granted_role from pivot_data
)
;
cc := q'[
WITH PIVOT_DATA AS (
SELECT *
FROM
(
SELECT USERNAME,GRANTED_ROLE
FROM DBA_USERS U LEFT OUTER JOIN DBA_ROLE_PRIVS R
ON U.USERNAME = R.GRANTEE
)
)
SELECT *
FROM PIVOT_DATA
PIVOT
(
COUNT(GRANTED_ROLE)
FOR GRANTED_ROLE
IN(]' || bb || q'[) -- Just an example
)
ORDER BY USERNAME ASC]';
open :rr for cc;
end;
/
SET PAGESIZE 200
SET LINESIZE 16000
print :rr
这是结果(只有小片段,因为它很宽很长)
-----------------------------------------------------------------------------------------------------------------------------------
USERNAME 'ADM_PARALLEL_EXECUTE_TASK' 'APEX_ADMINISTRATOR_ROLE' 'AQ_ADMINISTRATOR_ROLE' 'AQ_USER_ROLE'
------------------------------ --------------------------- ------------------------- ----------------------- ----------------------
ANONYMOUS 0 0 0 0
APEX_030200 0 0 0 0
APEX_PUBLIC_USER 0 0 0 0
APPQOSSYS 0 0 0 0
..............
IX 0 0 1 1
OWBSYS 0 0 1 1
看看这个例子:
variable rr refcursor declare bb varchar2(4000); cc varchar2( 30000 ); begin WITH PIVOT_DATA AS ( SELECT * FROM ( SELECT USERNAME,GRANTED_ROLE FROM DBA_USERS U LEFT OUTER JOIN DBA_ROLE_PRIVS R ON U.USERNAME = R.GRANTEE ) ) select ''''|| listagg( granted_role,''',''' ) within group( order by granted_role ) || '''' as x into bb from ( select distinct granted_role from pivot_data ) ; cc := q'[ WITH PIVOT_DATA AS ( SELECT * FROM ( SELECT USERNAME,GRANTED_ROLE FROM DBA_USERS U LEFT OUTER JOIN DBA_ROLE_PRIVS R ON U.USERNAME = R.GRANTEE ) ) SELECT * FROM PIVOT_DATA PIVOT ( COUNT(GRANTED_ROLE) FOR GRANTED_ROLE IN(]' || bb || q'[) -- Just an example ) ORDER BY USERNAME ASC]'; open :rr for cc; end; / SET PAGESIZE 200 SET LINESIZE 16000 print :rr
这是结果(只有小片段,因为它很宽很长)
----------------------------------------------------------------------------------------------------------------------------------- USERNAME 'ADM_PARALLEL_EXECUTE_TASK' 'APEX_ADMINISTRATOR_ROLE' 'AQ_ADMINISTRATOR_ROLE' 'AQ_USER_ROLE' ------------------------------ --------------------------- ------------------------- ----------------------- ---------------------- ANONYMOUS 0 0 0 0 APEX_030200 0 0 0 0 APEX_PUBLIC_USER 0 0 0 0 APPQOSSYS 0 0 0 0 .............. IX 0 0 1 1 OWBSYS 0 0 1 1