如何在SQL Server 2005中进行sql表的尴尬转移?

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我必须从sql Server旋转给定的表,但正常的数据透视表不起作用(据我所知).那么有人知道如何将表格旋转成所需的格式吗?

只是为了使问题更复杂,给定标签的列表可能会有所不同,并且可能会在任何给定时间出现新的标签名称.

鉴于数据

ID |  Label          |  Numerator  |  Denominator  |  Ratio 
---+-----------------+-------------+---------------+--------
1  |  LabelNameOne   |  41         |  10           |  4,1   
1  |  LabelNameTwo   |  0          |  0            |  0     
1  |  LabelNameThree |  21         |  10           |  2,1   
1  |  LabelNameFour  |  15         |  10           |  1,5   
2  |  LabelNameOne   |  19         |  19           |  1     
2  |  LabelNameTwo   |  0          |  0            |  0     
2  |  LabelNameThree |  15         |  16           |  0,9375
2  |  LabelNameFive  |  19         |  19           |  1     
2  |  LabelNameSix   |  17         |  17           |  1     
3  |  LabelNameOne   |  12         |  12           |  1     
3  |  LabelNameTwo   |  0          |  0            |  0     
3  |  LabelNameThree |  11         |  12           |  0,9167
3  |  LabelNameFour  |  12         |  12           |  1     
3  |  LabelNameSix   |  0          |  1            |  0

想要结果

ID | ValueType   | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix
---+-------------+--------------+--------------+----------------+---------------+---------------+--------------
1  | Numerator   | 41           | 0            | 21             | 15            |               |              
1  | Denominator | 10           | 0            | 10             | 10            |               |              
1  | Ratio       | 4,1          | 0            | 2,1            | 1,5           |               |              
2  | Numerator   | 19           | 0            | 15             |               | 19            | 17           
2  | Denominator | 19           | 0            | 16             |               | 19            | 17           
2  | Ratio       | 1            | 0            | 0,9375         |               | 1             | 1            
3  | Numerator   | 12           | 0            | 11             | 12            |               | 0            
3  | Denominator | 12           | 0            | 12             | 12            |               | 1            
3  | Ratio       | 1            | 0            | 0,9167         | 1             |               | 0

解决方法

这应该把你排除在外.它真的是一个UNPIVOT和一个PIVOT.请注意,您必须符合您的数据,因为UNPIVOT将所有数据放在同一列中.

请注意,我必须在内部动态sql中重新创建/重新填充表变量 – 通常在处理永久表时不需要这样做.

SET NOCOUNT ON ;

DECLARE @pivot_cols AS varchar(max) ;
DECLARE @src AS TABLE
    (
     ID int NOT NULL,Label varchar(14) NOT NULL,Numerator int NOT NULL,Denominator int NOT NULL,Ratio decimal(5,4) NOT NULL
    ) ;

DECLARE @label_order AS TABLE
    (
     Label varchar(14) NOT NULL,Sort int NOT NULL
    )

INSERT  INTO @src
VALUES  (1,'LabelNameOne',41,10,4.1) ;
INSERT  INTO @src
VALUES  (1,'LabelNameTwo',0) ;
INSERT  INTO @src
VALUES  (1,'LabelNameThree',21,2.1) ;
INSERT  INTO @src
VALUES  (1,'LabelNameFour',15,1.5) ;
INSERT  INTO @src
VALUES  (2,19,1) ;
INSERT  INTO @src
VALUES  (2,0) ;
INSERT  INTO @src
VALUES  (2,16,0.9375) ;
INSERT  INTO @src
VALUES  (2,'LabelNameFive','LabelNameSix',17,1) ;
INSERT  INTO @src
VALUES  (3,12,0) ;
INSERT  INTO @src
VALUES  (3,11,0.9167) ;
INSERT  INTO @src
VALUES  (3,1,0) ;

INSERT  INTO @label_order
VALUES  ('LabelNameOne',1) ;
INSERT  INTO @label_order
VALUES  ('LabelNameTwo',2) ;
INSERT  INTO @label_order
VALUES  ('LabelNameThree',3) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFour',4) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFive',5) ;
INSERT  INTO @label_order
VALUES  ('LabelNameSix',6) ;

WITH    Labels
          AS (
              SELECT  DISTINCT
                        src.Label,ISNULL(label_order.Sort,0) AS Sort
              FROM      @src AS src
              LEFT JOIN @label_order AS label_order
                        ON src.label = label_order.label
             )
    SELECT  @pivot_cols = COALESCE(@pivot_cols + ',','') + QUOTENAME(Label,'[')
    FROM    Labels
    ORDER BY Sort,Label ;

DECLARE @template AS varchar(max) ;

SET @template = '
DECLARE @src AS TABLE
    (
     ID int NOT NULL,4) NOT NULL
    ) ;

INSERT  INTO @src
VALUES  (1,''LabelNameOne'',''LabelNameTwo'',''LabelNameThree'',''LabelNameFour'',''LabelNameFive'',''LabelNameSix'',0) ;

WITH    src_conformed
          AS (
              SELECT    ID,Label,CAST (Numerator AS decimal(10,4)) AS Numerator,CAST (Denominator AS decimal(10,4)) AS Denominator,CAST (Ratio AS decimal(10,4)) AS Ratio
              FROM      @src
             ),UNPIVOTED
          AS (
              SELECT    *
              FROM      src_conformed UNPIVOT ( Val FOR Col IN (Numerator,Denominator,Ratio) ) AS unpvt
             )
    SELECT  *
    FROM    UNPIVOTED PIVOT ( SUM(Val) FOR Label IN ({@pivot_cols}) ) AS pvt
    ORDER BY ID,Col ;' ;

SET @template = REPLACE(@template,'{@pivot_cols}',@pivot_cols) ;

EXEC (@template) ;
原文链接:https://www.f2er.com/mssql/77109.html

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