如果我有下表
Hour Clicks Conversions 12:00 2 0 1:00 3 2 2:00 1 1
如何编写一个SELECT语句,在两列中分解它,所以我得到:
12:00 1 0 12:00 1 0 1:00 1 0 1:00 1 1 1:00 1 1 2:00 1 1
如果我不能用SELECT做到这一点,我如何用循环编写存储过程?
谢谢!
解决方法
这假设对于[Hour]的任何给定值,将只有一行.如果可能存在重复,我会首先聚合它们(我假设源已经是某种聚合).
DECLARE @x TABLE ([Hour] CHAR(5),Clicks INT,Conversions INT); INSERT @x SELECT '12:00',2,0 UNION ALL SELECT '13:00',3,2 UNION ALL SELECT '14:00',1,1; ;WITH x AS ( SELECT n = ROW_NUMBER() OVER (ORDER BY s1.[object_id]) FROM sys.all_columns AS s1 -- CROSS JOIN (SELECT 1 UNION ALL SELECT 2) AS s2 -- to double the rows if you need more ),y AS ( SELECT [Hour],Conversions,Clicks,m = MAX(CASE WHEN Conversions > Clicks THEN Conversions ELSE Clicks END) FROM @x GROUP BY [Hour],Clicks ) SELECT y.[Hour],Clicks = CASE WHEN Clicks < x.n THEN 0 ELSE 1 END,Conversions = CASE WHEN Conversions < x.n THEN 0 ELSE 1 END FROM x INNER JOIN y ON x.n <= y.m ORDER BY CONVERT(TIME,y.[Hour]),Conversions;