我有一个xml代码：
<begin>
<entry>
<lastname>gordon</lastname>
<NumberList>
<number>100</number>
<codelist>
<code>213</code>
<code>214</code>
<codelist>
<login>
<user>user1</user>
<user>user2</user>
</login>
<NumberList>
<address>
<addresslist>Jl. jalan pelan-pelan ke Bekasi,Indonesia</addresslist>
</address>
</entry>
<entry>
<lastname>mark</lastname>
<address>
<addresslist>Jl. jalan cepet-cepet ke Jakarta,Indonesia</addresslist>
</address>
</entry>
</begin>
我的代码：
FOR r IN (SELECT VALUE(p) col_val,EXTRACT(VALUE(P),'/entry/codelist') AS code,'/entry/login') AS login
FROM TABLE(XMLSequence(Extract(x,'/begin/entry'))) p)
LOOP
IF r.col_val.existsnode('/entry/lastname/text()') > 0
THEN
vc_lastname := r.col_val.extract('/sdnEntry/lastname/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/address/addresslist/text()') > 0
THEN
vc_address := r.col_val.extract('/sdnEntry/address/addresslist/text()').getstringval();
END IF;
IF r.col_val.existsnode('/entry/codelist/id/code/text()') > 0 AND r.col_val.existsnode('/entry/login/user/text()') > 0
THEN
FOR R1 IN (SELECT EXTRACTVALUE(VALUE(T1),'/codelist/code/text()') AS code
FROM TABLE(XMLSEQUENCE(EXTRACT(R.code,'/codelist'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R1.code||' - '||R2.address);
END LOOP;
FOR R2 IN (SELECT
EXTRACTVALUE(VALUE(T1),'/login/user/text()') AS user
FROM TABLE(XMLSEQUENCE(EXTRACT(R.address,'login/'))) T1)
LOOP
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName||' - '||R2.user||' - '||R2.address);
END LOOP;
ELSE
DBMS_OUTPUT.PUT_LINE(vc_uid||' - '||vc_firstName);
END IF;
我的问题：如何循环子节点,以便数据将如下所示：
LastName | Number | code | user | address gordon | 100 | 213 | user1 |Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon | 100 | 213 | user2 |Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon | 100 | 214 | user1 |Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon | 100 | 214 | user2 |Jl. jalan pelan-pelan ke Bekasi,Indonesia mark | Null | null | null |Jl. jalan cepet-cepet ke Jakarta,Indonesia
任何帮助将是欣赏.
解决方法
您可以使用XMLTable()函数获得所需的结果：
select q.Lastname,q.Numberid,s.codeid,w.LoginId,q.address
from t1 t
left join xmltable('/begin/entry'
passing t.xml_col
columns LastName varchar2(21) path 'lastname',NumberId number path 'NumberList/number',Address varchar2(201) path 'address/addresslist',CodeList XmlType Path 'NumberList/codelist/code',Logins XmlType Path 'NumberList/login/user'
) q
on (1=1)
left join xmltable('/code'
passing q.CodeList
columns CodeId number path '.') s
on (1=1)
left join xmltable('/user'
passing q.Logins
columns LoginId varchar2(11) path '.') w
on (1=1)
Lastname Numberid Codeid Loginid Address --------------------------------------------------------------------------- gordon 100 213 user1 Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon 100 213 user2 Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon 100 214 user1 Jl. jalan pelan-pelan ke Bekasi,Indonesia gordon 100 214 user2 Jl. jalan pelan-pelan ke Bekasi,Indonesia mark null null null Jl. jalan cepet-cepet ke Jakarta,Indonesia
Find out more关于XMLTable()函数.
注意：使用11.2.0.2之前的Oracle版本,当cursor_sharing参数设置为FORCE或SIMILAR(从11.2开始不建议使用)时,您可能会遇到某些类型的XML查询的ORA-1780错误(错误8545377).将cursor_sharing参数设置为EXACT(默认值),将解决问题.
