解决方法
CREATE TABLE TABLE_NAME (
`empid_number` int ( 11) NOT NULL auto_increment,`employee` varchar ( 100) NOT NULL,`manager_number` int ( 11) NOT NULL,PRIMARY KEY (`empid_number`),CONSTRAINT `manager_references_employee`
FOREIGN KEY (`manager_number`) REFERENCES (`empid_number`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
希望有帮助！
