一张表（ColumnTable）的结构如下图所示
当前需要实现的功能：通过Number的值为67来获取当前的节点ID、父节点ID
递归实现sql语句：
代码如下:
with znieyu as
(
select c.Id,c.FatherId,0 as lv1 from ColumnTable c where c.Number=67
union all
select c.Id,lv1-1 from znieyu z
inner join ColumnTable c
on z.FatherId=c.Id
)
select znieyu.Id,znieyu.FatherId,znieyu.lv1 as lv from znieyu
(
select c.Id,c.FatherId,0 as lv1 from ColumnTable c where c.Number=67
union all
select c.Id,lv1-1 from znieyu z
inner join ColumnTable c
on z.FatherId=c.Id
)
select znieyu.Id,znieyu.FatherId,znieyu.lv1 as lv from znieyu
实现的效果：
满足条件67ID为6的递归-->6-->2(LV0)-->1(LV-1)-->0(LV-2)
满足条件67ID为8的递归-->8-->5(LV0)-->2(LV-1)-->1(LV-2)-->0(LV-3)
很简单的一个sql递归，记录下来...
