我想格式化一个数字看起来如下“1,234”或“1,234,432”或“123,456,789”,你明白了.我尝试这样做如下;
function reformatint(i)
local length = string.len(i)
for v = 1,math.floor(length/3) do
for k = 1,3 do
newint = string.sub(mystring,-k*v)
end
newint = ','..newint
end
return newint
end@H_502_3@
正如你所看到我尝试失败,问题是我无法弄清楚我正在运行的程序有什么问题,拒绝向我发回错误.
解决方法
这是一个将负数和小数部分考虑在内的函数：
function format_int(number)
local i,j,minus,int,fraction = tostring(number):find('([-]?)(%d+)([.]?%d*)')
-- reverse the int-string and append a comma to all blocks of 3 digits
int = int:reverse():gsub("(%d%d%d)","%1,")
-- reverse the int-string back remove an optional comma and put the
-- optional minus and fractional part back
return minus .. int:reverse():gsub("^,","") .. fraction
end
assert(format_int(1234) == '1,234')
assert(format_int(1234567) == '1,567')
assert(format_int(123456789) == '123,789')
assert(format_int(123456789.1234) == '123,789.1234')
assert(format_int(-123456789.) == '-123,789')
assert(format_int(-123456789.1234) == '-123,789.1234')
assert(format_int('-123456789.1234') == '-123,789.1234')
print('All tests passed!')@H_502_3@