我有一个项目,使用automake创建配置和所有相关文件(我使用autoreconf命令来制作所有这些东西).因此,我正在尝试设置一些条件文件,以便在项目编译macOS(OS X),Windows或
Linux时进行编译.但它失败了以下内容：
$autoreconf -i .. src/Makefile.am:30: error: LINUX does not appear in AM_CONDITIONAL autoreconf: automake Failed with exit status: 1
包含Makefile.am中的错误的部分如下：
if OSX
butt_SOURCES += CurrentTrackOSX.h CurrentTrackOSX.m
endif
if LINUX
butt_SOURCES += currentTrack.h currentTrackLinux.cpp
endif
if WINDOWS
butt_SOURCES += currentTrack.h currentTrack.cpp
endif
我的问题是,如何检查操作系统是否为Linux？如果有可能,有没有更好的方法来检查automake中的操作系统？
解决方法
您可以检测它
directly in the Makefile,或者在配置源文件(可能是configure.ac)中定义条件,因为您使用的是autoreconf：
# AC_CANONICAL_HOST is needed to access the 'host_os' variable
AC_CANONICAL_HOST
build_linux=no
build_windows=no
build_mac=no
# Detect the target system
case "${host_os}" in
linux*)
build_linux=yes
;;
cygwin*|mingw*)
build_windows=yes
;;
darwin*)
build_mac=yes
;;
*)
AC_MSG_ERROR(["OS $host_os is not supported"])
;;
esac
# Pass the conditionals to automake
AM_CONDITIONAL([LINUX],[test "$build_linux" = "yes"])
AM_CONDITIONAL([WINDOWS],[test "$build_windows" = "yes"])
AM_CONDITIONAL([OSX],[test "$build_mac" = "yes"])
Note:
host_osrefers to the target system,so if you are cross-compiling it sets the OS conditional of the system you are compiling to.
