linux – svn status | sort – 不对输出进行排序

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我想排序svn状态输出,但不知何故这个命令

  1. svn status | sort

不排序输出.
你知道为什么吗?

例如:

  1. $svn status
  2. ? idrd
  3. ? core.7319
  4. ? difftest
  5. ? core.29328
  6. A + rf_common/ext_api.sav
  7. D rf_common/ext_api/firewall_defs.h
  8. D rf_common/ext_api/rf_macro.h
  9. ? firewall/src/hash2tuple.cpp.sav
  10. ! firewall/src/hash2tuple.cpp
  11. M main.cpp
  12. M makefile
  13. $svn status | sort
  14. A + rf_common/ext_api.sav
  15. ? core.29328
  16. ? core.7319
  17. ? difftest
  18. D rf_common/ext_api
  19. D rf_common/ext_api/firewall_defs.h
  20. D rf_common/ext_api/rf_macro.h
  21. ! firewall/src/hash2tuple.cpp
  22. ? firewall/src/hash2tuple.cpp.sav
  23. ? idrd
  24. M main.cpp
  25. M makefile

例如,问号没有排序.

最佳答案
您似乎希望排序禁用最后的比较.

  1. sort -s -k1,1

你的输入会产生:

  1. ! firewall/src/hash2tuple.cpp
  2. ? idrd
  3. ? core.7319
  4. ? difftest
  5. ? core.29328
  6. ? firewall/src/hash2tuple.cpp.sav
  7. A + rf_common/ext_api.sav
  8. D rf_common/ext_api/firewall_defs.h
  9. D rf_common/ext_api/rf_macro.h
  10. M main.cpp
  11. M makefile

引用男人排序:

  1. -s,--stable
  2. stabilize sort by disabling last-resort comparison

sort invocation开始:

Finally,as a last resort when all keys compare equal,sort compares
entire lines as if no ordering options other than --reverse (-r)
were specified. The --stable (-s) option disables this last-resort
comparison so that lines in which all fields compare equal are left in
their original relative order.

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