好吧这可能是一个很难的,我有一个pyGTK应用程序,由于我无法捕获/控制的X Window错误导致随机崩溃.
所以我创建了一个包装器,一旦检测到崩溃就重新启动应用程序,现在出现了问题,当用户注销或关闭系统时,应用程序以状态1退出.但是在某些X错误上它也会这样做.
所以我尝试了任何事情以捕获关闭/注销,但没有成功,这是我尝试过的:
import pygtk
import gtk
import sys
class Test(gtk.Window):
def delete_event(self,widget,event,data=None):
open("delete_event","wb")
def destroy_event(self,data=None):
open("destroy_event","wb")
def destroy_event2(self,data=None):
open("destroy_event2","wb")
def __init__(self):
gtk.Window.__init__(self,gtk.WINDOW_TOPLEVEL)
self.show()
self.connect("delete_event",self.delete_event)
self.connect("destroy",self.destroy_event)
self.connect("destroy-event",self.destroy_event2)
def foo():
open("add_event","wb")
def ex():
open("sys_event","wb")
from signal import *
def clean(sig):
f = open("sig_event","wb")
f.write(str(sig))
f.close()
exit(0)
for sig in (SIGABRT,SIGILL,SIGINT,SIGSEGV,SIGTERM):
signal(sig,lambda *args: clean(sig))
def at():
open("at_event","wb")
import atexit
atexit.register(at)
f = Test()
sys.exitfunc = ex
gtk.quit_add(gtk.main_level(),foo)
gtk.main()
open("exit_event","wb")
其中没有一个成功,是否有任何低级方法来检测系统关闭?谷歌没有找到与此相关的任何内容.
我想一定有办法,对吗? :/
编辑:
好的,更多的东西.
我已经创建了这个shell脚本:
#!/bin/bash
trap test_term TERM
trap test_hup HUP
test_term(){
echo "teeeeeeeeeerm" >~/Desktop/term.info
exit 0
}
test_hup(){
echo "huuuuuuuuuuup" >~/Desktop/hup.info
exit 1
}
while [ true ]
do
echo "idle..."
sleep 2
done
并且还创建了一个.desktop文件来运行它:
[Desktop Entry]
Name=Kittens
GenericName=Kittens
Comment=Kitten Script
Exec=kittens
StartupNotify=true
Terminal=false
Encoding=UTF-8
Type=Application
Categories=Network;GTK;
Name[de_DE]=Kittens
通常这应该在注销时创建术语文件,并在使用&启动时创建hup文件.但不是我的系统. GDM根本不关心脚本,当我重新编写时,它仍在运行.
我也试过使用shopt -s huponexit,但没有成功.
EDIT2:
这里还有一些关于真实代码的更多信息,整个事情看起来像这样:
Wrapper Script,that catches errors and restarts the programm
-> Main Programm with GTK Mainloop
-> Background Updater Thread
流程是这样的:
Start Wrapper
-> enter restart loop
while restarts < max:
-> start program
-> check return code
-> write error to file or exit the wrapper on 0
现在关机时,启动程序返回1.这意味着要么是hanup还是父进程终止,主要问题是找出这两个中的哪一个刚刚发生.
X错误也导致1.陷阱中的陷阱不起作用.
如果你想看看实际的代码,请在GitHub上查看:
http://github.com/BonsaiDen/Atarashii
最佳答案
好的,我终于找到了解决方案:)
在这种情况下,你根本不能依赖信号.您必须连接到桌面会话才能收到注销即将发生的通知.
import gnome.ui
gnome.program_init('Program',self.version) # This is going to trigger a warning that program name has been set twice,you can ignore this,it seems to be a problem with a recent version of glib,the warning is all over the place out there
client = gnome.ui.master_client() # connect us to gnome session manager,we need to init the program before this
client.connect('save-yourself',self.on_logout) # This gets called when the user confirms the logout/shutdown
client.connect('shutdown-cancelled',self.on_logout_cancel) # This gets called when the logout/shutdown is canceled
client.connect('die',self.on_logout) # Don't know when this gets called it never got in my tests
def on_logout(self,*args):
# save settings an create a file that tells the wrapper that we have exited correctly!
# we'll still return with status code 1,but that's just gtk crashing somehow
def on_logout_cancel(self,*args):
# simply delete the logout file if it exists
这里有一个重要的注意事项:不要尝试在on_logout中退出程序,如果这样做,GNOME将无法识别您的程序已退出,并将为您提供某些程序仍在运行的对话框.