从OS X交叉编译到Linux

@H_502_1@我想从OS X 10.7 Eclipse构建系统编译Linux服务器的二进制文件.这意味着GCC交叉编译器.我从本机4.7.1开始,为主机4.7.1射击.

@H_502_1@大多数在线说明都特定于嵌入式开发.我想使用libstdc -v3和glibc,这使它有点不同.

@H_502_1@成功的是什么：

@H_502_1@>安装包

@H_502_1@

port install gcc47
export CC=gcc-mp-47
export LD=ld-mp-47
export CXX=g++-mp-47
export CPP=cpp-mp-47

port install gmake
ln /opt/local/bin/gmake /opt/local/bin/make

port install gsed
ln /opt/local/bin/gsed /opt/local/bin/sed

port install gawk
port install autoconf
port install msgfmt

@H_502_1@>制作并安装binutils-2.22
> make all-gcc并make install-gcc

@H_502_1@使用以下配置：

@H_502_1@

@H_502_1@$../gcc/configure –enable-languages=c,c++,objc,obj-c++ –with-gmp=/opt/local –with-mpfr=/opt/local –with-mpc=/opt/local –prefix=/usr/local/cross/linux –target=x86_64-pc-linux-gnu –disable-nls

@H_502_1@>将构建环境指向交叉编译器

@H_502_1@

export CC=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-gcc
export LD=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-ld
export AR=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-ar
export CXX=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-g++
export CPP=/usr/local/cross/linux/bin/x86_64-pc-linux-gnu-cpp

@H_502_1@>使用配置构建glibc-2.16

@H_502_1@

@H_502_1@../glibc/configure –host=x86_64-pc-linux-gnu –build=x86_64-apple-darwin11 –prefix=/usr/local/cross/linux/ –with-binutils=/usr/local/cross/linux/bin/ –with-headers=/usr/local/cross/linux/include/ libc_cv_forced_unwind=yes libc_cv_ctors_header=yes libc_cv_c_cleanup=yes

@H_502_1@失败：

@H_502_1@glibc构建不久就失败了.此消息多次出现：

@H_502_1@

In file included from ./sysdeps/unix/sysdep.h:20:0,from ./sysdeps/unix/x86_64/sysdep.h:18,from sysdeps/unix/sysv/linux/x86_64/sysdep.h:22,from


@H_502_1@不过,这可能是正常的.
@H_502_1@然后它无法生成stdio_lim.h.使用make -d,我得到这个：
@H_502_1@
          Successfully remade target file `/Users/dkrauss/Documents/work/glibc-build/csu/abi-tag.h'.
          Considering target file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
           File `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h' does not exist.
           Looking for an implicit rule for `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
           Trying pattern rule with stem `lim'.
           Trying implicit prerequisite `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
           Found an implicit rule for `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.
            Considering target file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
            Recently tried and Failed to update file `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st'.
make[2]: *** No rule to make target `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.st',needed by `/Users/dkrauss/Documents/work/glibc-build/bits/stdio_lim.h'.  Stop.

@H_502_1@这是它尝试以位为单位构建的第一个头.有一个文件stdio_lim.h.in,它是目录中唯一的.in文件.是否应该将某些规则连接到.in？


最佳答案
为了正确构建glibc,您需要来自Linux系统的头文件 – 可能内核头文件就足够了.
@H_502_1@这是因为在该系统的软件的任何正常构建中都需要这些头,并且在交叉编译时也是如此.
@H_502_1@自从我创建交叉编译器以来已经很长时间了,所以我不能告诉你如何使用glibc来构建标题,但我相信它可以直接进行.
 原文链接：https://www.f2er.com/linux/440916.html

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