我想模拟许多重要的新闻事件.我通过使用XTestFakeKeyEvent找到了一个解决方案,但是当我模拟超过210次时,我的程序提出了“达到的最大客户端数”分段错误.我不知道如何解决这个问题.
我的代码在这里：
@H_301_7@#include dio.h>
#define PRESS_UP 0
#define PRESS_DOWN 1
#define PRESS_LEFT 2
#define PRESS_RIGHT 3
#define PRESS_ENTER 4
#define PRESS_ESC 5
#define PRESS_HOME 6
Display *display;
unsigned int keycode;
int press(int key){
display = XOpenDisplay(NULL);
if(key == PRESS_UP)
keycode = XKeysymToKeycode(display,XK_Up);
else if(key == PRESS_DOWN)
keycode = XKeysymToKeycode(display,XK_Down);
else if(key == PRESS_LEFT)
keycode = XKeysymToKeycode(display,XK_Left);
else if(key == PRESS_RIGHT)
keycode = XKeysymToKeycode(display,XK_Right);
else if(key == PRESS_ENTER)
keycode = XKeysymToKeycode(display,XK_Return);
else if(key == PRESS_ESC)
keycode = XKeysymToKeycode(display,XK_Escape);
else if(key == PRESS_HOME)
keycode = XKeysymToKeycode(display,XK_Home);
XTestFakeKeyEvent(display,keycode,True,0);
XTestFakeKeyEvent(display,False,0);
XFlush(display);
return 0;
}
int main(int argc,char *argv[]){
int count = 0;
while (count < 500){
press(PRESS_UP);
printf("count =%d\n",count);
count ++;
}
}
输出：
@H_301_7@$gcc -lXtst -lX11 Util_KeyPressSimulator.c
$./a.out
count =0
^[[Acount =1
^[[Acount =2
...
^[[Acount =208
^[[Acount =209
^[[Acount =210
^[[AMaximum number of clients reachedSegmentation fault
有人请帮忙,谢谢.
最佳答案
