@H_301_1@我有一个文件导出了一堆需要删除的文件名.我需要知道如何删除每个文件而不必在命令行一次发出一个文件.
我已经考虑过在for循环中把它括起来,这可能会起作用,但是想知道是否有一个更简单,甚至更好的解决方案来做到这一点.
谢谢.
解决方法
rm -rf `cat /path/to/filename`
“字符可以用$()替换
来自bash手册页：
Command Substitution
Command substitution allows the output of a command to replace the command
name. There are two forms:
$(command)
or
`command`
Bash performs the expansion by executing command and replacing the command
substitution with the standard output of the command,with any trailing
newlines deleted. Embedded newlines are not deleted,but they may be
removed during word splitting. The command substitution $(cat file) can
be replaced by the equivalent but faster $(< file).
When the old-style backquote form of substitution is used,backslash
retains its literal meaning except when followed by $,`,or \. The first
backquote not preceded by a backslash terminates the command substitution.
When using the $(command) form,all characters between the parentheses
make up the command; none are treated specially.
Command substitutions may be nested. To nest when using the backquoted
form,escape the inner backquotes with backslashes.
If the substitution appears within double quotes,word splitting and path‐
name expansion are not performed on the results.
