我有一个包含如下列的文件：
chr1 91.4062 chr10 97.9150 chr11 116.7630 chr12 106.7870 chr13 116.1050 chr14 126.2180 chr15 110.2320 chr16 96.8076 chr17 113.5970 chr18 86.1011 chr19 130.6770 chr2 111.4620 chr20 68.4864 chr21 107.0810 chr22 140.7750 chr23 110.9590 chr24 68.4785 chr25 102.2080 chr26 72.2762 chr27 96.2213 chr28 85.5570 chr29 126.3800 chr3 116.1830 chr30 89.5663 chr31 89.1227 chr32 128.6190 chr4 117.3620 chr5 78.1921 chr6 85.4915 chr7 107.2620 chr8 112.9560 chr9 69.0250 chrX 66.0736
我想基于第1列对其进行排序,输出应如下所示：
chr1 91.4062 chr2 111.4620 chr3 116.1830 chr4 117.3620 chr5 78.1921 chr6 85.4915 chr7 107.2620 chr8 112.9560 chr9 69.0250 chr10 97.9150 chr11 116.7630 chr12 106.7870 chr13 116.1050 chr14 126.2180 chr15 110.2320 chr16 96.8076 chr17 113.5970 chr18 86.1011 chr19 130.6770 chr20 68.4864 chr21 107.0810 chr22 140.7750 chr23 110.9590 chr24 68.4785 chr25 102.2080 chr26 72.2762 chr27 96.2213 chr28 85.5570 chr29 126.3800 chr30 89.5663 chr31 89.1227 chr32 128.6190 chrX 66.0736
任何使用linux命令的解决方案都会有帮助.
解决方法
排序-V救援：
sort -V file
从男人那种：
-V,–version-sort
natural sort of (version) numbers within text
如果您在sort命令中没有-V选项,则有另一种方法：从第4个字符(-k1.4)开始按第一列排序,然后按数字排序(-n).
sort -k1.4 -n file
在这两种情况下,输出如下：
chrX 66.0736 chr1 91.4062 chr2 111.4620 chr3 116.1830 chr4 117.3620 ... chr26 72.2762 chr27 96.2213 chr28 85.5570 chr29 126.3800 chr30 89.5663 chr31 89.1227 chr32 128.6190
