如何用curl做keepalive http请求?

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如何在同一连接中从同一Web服务器请求多个页面

因此客户端需要为每个请求提取响应,当然服务器的工作就是按照请求的顺序进行响应.

谁知道诀窍?

解决方法

我不知道你是否真的意味着“并发”,但从描述中我相信你只想重用连接.如果只是对同一服务器执行两个请求,则应重用该连接

persistant.c

/* get the first document */ 
curl_easy_setopt(curl,CURLOPT_URL,"http://example.com/");
res = curl_easy_perform(curl);


/* get another document from the same server using the same
   connection */ 
curl_easy_setopt(curl,"http://example.com/docs/");
res = curl_easy_perform(curl);

以下是输出的部分内容

* About to connect() to example.com port 80 (#0)
*   Trying 192.0.32.10... * connected
* Connected to example.com (192.0.32.10) port 80 (#0)

[...]

* HTTP/1.0 connection set to keep alive!
< Connection: Keep-Alive
Connection: Keep-Alive

[...]

* Connection #0 to host example.com left intact
* Re-using existing connection! (#0) with host example.com
* Connected to example.com (192.0.32.10) port 80 (#0)

编辑根据评论

在这种情况下,您需要多接口.多重联系说:

Enable multiple simultaneous transfers in the same thread without
making it complicated for the
application.

有关示例,请参阅multi-double.c(“只需下载两个HTTP文件!”).

原文链接:https://www.f2er.com/linux/394223.html

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