我一直试图处理laravel抛出的异常一段时间.我尝试过很多东西,但似乎没有用.以下是我使用的语法：
public function render($request,Exception $e)
{
//404 page when a model is not found
if ($e instanceof ModelNotFoundException) {
return response()->view('errors.404',[],404);
}elseif ($e instanceof \AuthorizationException) {
return response()->view('errors.403',403);
}elseif ($e instanceof TokenMismatchException) {
Flash::error('Sorry,your session seems to have expired. Please try again.');
return redirect('/');
}elseif ($e instanceof \ErrorException) {
return response()->view('errors.500',500);
}else {
return response()->view('errors.500',500);
}
// return parent::render($request,$e);
}
use Exception; use Illuminate\Auth\Access\AuthorizationException; use Illuminate\Database\Eloquent\ModelNotFoundException; use Illuminate\Foundation\Exceptions\Handler as ExceptionHandler; use Illuminate\Session\TokenMismatchException; use Illuminate\Validation\ValidationException; use Symfony\Component\HttpKernel\Exception\HttpException;
protected $dontReport = [
AuthorizationException::class,HttpException::class,ModelNotFoundException::class,ValidationException::class,TokenMismatchException::class,];
谁能帮我这个？我已经坚持了几天.任何帮助,将不胜感激.
解决方法
原因是框架排除了这些例外情况,因此不予报告.请参阅
here以获取参考.
由于定义排除异常的属性受到保护,您应该能够在app / Exceptions / Handler.PHP文件中覆盖它.您不应该删除所有这些异常,而只删除您真正想要捕获的异常.只需将以下行添加到Handler.PHP：
/**
* A list of the internal exception types that should not be reported.
*
* @var array
*/
protected $internalDontReport = [
AuthenticationException::class,HttpResponseException::class,];
您还必须为所有类添加use语句.
(请注意,这是Laravel 5.6的排除例外列表 – 如果您使用的是其他版本,则可能必须使用git blame或其他分支来查找适合您版本的正确列表.)
