我终于找到了一种创建这些测试的方法,但它感觉就像是使用setLaravel和setApplication调用的一个黑客.

有没有更好的方法来做到这一点？我希望我可以将我的模拟实例添加到Laravel IoC容器中,并让它创建用于测试所有正确设置的命令.恐怕我的单元测试会随着更新的Laravel版本而轻松破解.

这是我的单元测试：

使用陈述：

use Mockery as m;
use App\Console\Commands\AddClientCommand;
use Symfony\Component\Console\Tester\CommandTester;

建立

public function setUp() {
    parent::setUp();

    $this->store = m::mock('App\Services\Store');

    $this->command = new AddClientCommand($this->store);

    // Taken from laravel/framework artisan command unit tests
    // (e.g. tests/Database/DatabaseMigrationRollbackCommandTest.PHP)
    $this->command->setLaravel($this->app->make('Illuminate\Contracts\Foundation\Application'));

    // required to provide input to command questions (provides command->getHelper())
    // Taken from ??? when I first built my command tests in Laravel 4.2
    $this->command->setApplication($this->app->make('Symfony\Component\Console\Application'));
}

输入作为命令参数提供.检查控制台输出

public function testReadCommandOutput() {
    $commandTester = new CommandTester($this->command);

    $result = $commandTester->execute([
        '--client-name' => 'New Client',]);

    $this->assertSame(0,$result);
    $templatePath = $this->testTemplate;

    // Check console output
    $this->assertEquals(1,preg_match('/^Client \'New Client\' was added./m',$commandTester->getDisplay()));
}

模拟键盘提供的输入

public function testAnswerQuestions() {
    $commandTester = new CommandTester($this->command);

    // Simulate keyboard input in console for new client
    $inputs = $this->command->getHelper('question');
    $inputs->setInputStream($this->getInputStream("New Client\n"));
    $result = $commandTester->execute([]);

    $this->assertSame(0,$commandTester->getDisplay()));
}

protected function getInputStream($input) {
    $stream = fopen('PHP://memory','r+',false);
    fputs($stream,$input);
    rewind($stream);
    return $stream;
}

更新

>这不适用于Laravel 5.1 #11946

public function getConsoleResponse()
{
    $kernel = $this->app->make(Illuminate\Contracts\Console\Kernel::class);
    $status = $kernel->handle(
        $input = new Symfony\Component\Console\Input\ArrayInput([
            'command' => 'test:command',// put your command name here
        ]),$output = new Symfony\Component\Console\Output\BufferedOutput
    );

    return json_decode($output->fetch(),true);
}