我需要序列化包含具有getter但没有setter的属性的对象(OpenTK.Vector2).我希望一般可以忽略这些属性,否则我最终会从具有两个相关数据片段(X和Y)的对象中充分夸大
JSON.
代码：
JsonSerializerSettings settings = new JsonSerializerSettings { ReferenceLoopHandling = ReferenceLoopHandling.Ignore };
Vector2 v = new Vector2 { X = 1,Y = 0 };
string json = JsonConvert.SerializeObject(v,settings);
生成字符串：
{
"X" : 1.0,"Y" : 0.0,"Length" : 1.0,"LengthFast" : 1.0016948,"LengthSquared" : 1.0,"PerpendicularRight" : {
"X" : 0.0,"Y" : -1.0,"PerpendicularRight" : {
"X" : -1.0,"PerpendicularRight" : {
"X" : 0.0,"Y" : 1.0,"LengthSquared" : 1.0
}
},"Yx" : {
"X" : -1.0,"LengthSquared" : 1.0
}
}
},"PerpendicularLeft" : {
"X" : 0.0,"PerpendicularLeft" : {
"X" : -1.0,"PerpendicularLeft" : {
"X" : 0.0,"LengthSquared" : 1.0
},"Yx" : {
"X" : 0.0,"LengthSquared" : 1.0
}
}
},"Yx" : {
"X" : 0.0,"LengthSquared" : 1.0
}
}
}
}
如何让序列化程序忽略这些其他属性？
解决方法
由于您无法修改OpenTK.Vector2结构以将[JsonIgnore]属性添加到get-only属性,因此最简单的方法可能是为其编写自己的
JsonConverter：
public class Vector2Converter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(OpenTK.Vector2);
}
public override object ReadJson(JsonReader reader,Type objectType,object existingValue,JsonSerializer serializer)
{
var temp = JObject.Load(reader);
return new OpenTK.Vector2(((float?)temp["X"]).GetValueOrDefault(),((float?)temp["Y"]).GetValueOrDefault());
}
public override void WriteJson(JsonWriter writer,object value,JsonSerializer serializer)
{
var vec = (OpenTK.Vector2)value;
serializer.Serialize(writer,new { X = vec.X,Y = vec.Y});
}
}
然后使用它像：
var settings = new JsonSerializerSettings();
settings.Converters.Add(new Vector2Converter());
Vector2 v = new Vector2 { X = 1,Y = 0 };
string json = JsonConvert.SerializeObject(v,settings);
Debug.WriteLine(json);
哪个产生
06002
但是如果你真的想要忽略所有类和结构上的所有get-only属性(可能会产生无法预料的后果),请参见：Is there a way to ignore get-only properties in Json.NET without using JsonIgnore attributes?.