Failed to load resource: the server responded with a status of 500 (Internal Server Error) ，

@H_301_8@public String ajaxgetname()
@H_301_8@{@H_301_8@
@H_301_8@System.out.println("ajaxgetname------------id:" +ajaxid);
@H_301_8@Staff s=staffService.getOneStaff(ajaxid);
@H_301_8@
@H_301_8@HttpServletResponse res = ServletActionContext.getResponse();
@H_301_8@ PrintWriter out = null;
@H_301_8@try {
@H_301_8@out = res.getWriter();
@H_301_8@} catch (IOException e) {
@H_301_8@// TODO Auto-generated catch block
@H_301_8@e.printStackTrace();
@H_301_8@}
@H_301_8@System.out.println("ajax取得名字：jsonobject前"+s.getName()); //这里能执行到
@H_301_8@JSONObject json = new JSONObject();
@H_301_8@json=JSONObject.fromObject(s);
@H_301_8@
@H_301_8@System.out.println("发送的json："+json.toString()); //这句输出不了
@H_301_8@out.print(json);
@H_301_8@out.flush();
@H_301_8@if(null != out){
@H_301_8@ out.close();//如果不关闭的话，ajax的回调函数不会调用
@H_301_8@ }


return SUCCESS;
@H_301_8@}

我会怎么解决呢？