我正在使用Jersey来使我的一些服务RESTful.
我的REST服务调用返回给我
{"param1":"value1","param2":"value2",...."paramN":"valueN"}
但是,我希望它能够回归
["param1":"value1",...."paramN":"valueN"]
我需要在下面的代码中做出哪些更改？
@GET
@Produces(MediaType.APPLICATION_JSON)
public List<com.abc.def.rest.model.SimplePojo> getSomeList() {
/*
Do something
*/
return listOfPojos;
}
我的web.xml文件的一部分看起来像这样
<servlet>
<servlet-name>Abc Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.abc.def.rest</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
谢谢！
您可以使用Person POJO定义您的服务方法,如下所示：
原文链接：https://www.f2er.com/json/288470.html@GET
@Produces("application/json")
@Path("/list")
public String getList(){
List<Person> persons = new ArrayList<>();
persons.add(new Person("1","2"));
persons.add(new Person("3","4"));
persons.add(new Person("5","6"));
// takes advantage to toString() implementation to format as [a,b,c]
return persons.toString();
}
POJO课程：
@XmlRootElement
public class Person {
@XmlElement(name="fn")
String fn;
@XmlElement(name="ln")
String ln;
public Person(){
}
public Person(String fn,String ln) {
this.fn = fn;
this.ln = ln;
}
@Override
public String toString(){
try {
// takes advantage of toString() implementation to format {"a":"b"}
return new JSONObject().put("fn",fn).put("ln",ln).toString();
} catch (JSONException e) {
return null;
}
}
}
结果如下：
[{"fn":"1","ln":"2"},{"fn":"3","ln":"4"},{"fn":"5","ln":"6"}]