我在函数内部有一个Promise链,我想console.log从链中2个函数返回的值.我该怎么做？使用我当前的代码,我从si.cpuTemperature()获取值,然后未定义,但我想从si.cpu()然后从si.cpuTemperature()获取值.
@H_404_6@const si = require('systeminformation'); function getcpuInfo() { return new Promise((resolve) => { resolve(); console.log("Gathering cpu information..."); return si.cpu() // .then(data => cpuInfo = data) - no need for this,the promise will resolve with "data" .catch(err => console.log(err)); // note,doing this will mean on error,this function will return a RESOLVED (not rejected) value of `undefined` }) .then(() => { return si.cpuTemperature().catch(err => console.log(err)); }); } getcpuInfo().then((data1,data2) => console.log(data1,data2));
最佳答案
从docs开始,
systeminformation.method()返回一个promise.因此,您实际上不需要将其包装在promise构造函数中,即new Promise()
要获取cpu和温度,因为它们彼此不依赖,所以可以将并行承诺与异步函数一起使用,也可以只使用并行承诺
@H_404_6@async function getcpuAndTemperature() { const [cpu,temperature] = await Promise.all([ si.cpu(),si.cpuTemperature() ]) console.log(cpu,temperature) }
要么
@H_404_6@function getcpuInfo() { return Promise.all([ si.cpu(),si.cpuTemperature() ]) .then(([cpu,temperature]) => { console.log(cpu,temperature) }) }
