我已经阅读了
this question并尝试从Swift中的AFNetworking的responSEObject解析JSON,但结果总是为零.
以下摘自我的代码：
let manager = AFHTTPRequestOperationManager()
manager.requestSerializer = AFJSONRequestSerializer()
manager.responseSerializer = AFJSONResponseSerializer()
manager.requestSerializer.setAuthorizationHeaderFieldWithUsername(username,password: password)
manager.POST("endpoint-that-respond-token-in-json",parameters: nil,success: { (operation: AFHTTPRequestOperation!,responSEObject: AnyObject!) in
println(responSEObject.description) // { token = "bd8f26da-219a-4a88-be80-b09207dfc067"; }
var x: NSString = responSEObject.description
var error: NSError?
var data = x.JSONString().dataUsingEncoding(NSUTF8StringEncoding)
println(data) // <227b5c6e 20202020 746f6b65 6e203d20 5c226539 35613462 36642d38 6361612d 34343537 2d623937 612d3330 63613236 62316338 34315c22 3b5c6e7d 22>
var dataString = NSString(data: data,encoding: NSUTF8StringEncoding)
println(dataString) // "{\n token = \"e95a4b6d-8caa-4457-b97a-30ca26b1c841\";\n}"
var json = NSJSONSerialization.JSONObjectWithData(data,options: NSJSONReadingOptions.MutableContainers,error: &error) as NSDictionary!
println(json) // nil
},failure: { (operation: AFHTTPRequestOperation!,error: NSError!) in
println(error)
})
注：
var json = NSJSONSerialization.JSONObjectWithData(data,error: &error) as NSDictionary // without "!" I will get EXC_BAD_INSTRUCTION at run time.
解决方法
您可以将responSEObject强制转换为字典
例如
manager.POST("endpoint-that-respond-token-in-json",responSEObject: AnyObject!) in
println(responSEObject.description) // { token = "bd8f26da-219a-4a88-be80-b09207dfc067"; }
let responseDict = response as Dictionary<String,AnyObject>
var token = responseDict["token"] as String!
println(token)
},error: NSError!) in
})
附：从字典返回的值总是可选的
编辑：在Xcode6 beta2发布后,上面的代码不再起作用了.需要先将其强制转换为AnyObject,然后再转换为字符串
let token : String? = (responseDict["token"] as AnyObject?) as? String
