根据胡子RFC
A {{name}} tag in a basic template will try to find the name key in
the current context. If there is no name key,nothing will be
rendered.
因此我期待这样：
var template = '{{#anArray}}{{aString}}{{/anArray}}';
var json = {
"aString":"ABC","anArray": [1,{"aString":"DEF"}]
};
给我一次渲染：
"DEF"
但是,mustache.js会在父级范围内查找值.这给了我
"ABCDEF"
上下文实际上意味着包括所有父母范围吗？
解决方法
简短回答：是的.
更长的答案. Context.prototype.lookup执行while循环,在当前上下文中查找标记,并且它是父上下文,同时存在父上下文.
相关的代码：
Context.prototype.lookup = function (name) {
var value = this._cache[name];
if (!value) {
if (name === ".") {
value = this.view;
} else {
var context = this;
//Iterate ancestor contexts
while (context) {
if (name.indexOf(".") > 0) {
var names = name.split("."),i = 0;
value = context.view;
while (value && i < names.length) {
value = value[names[i++]];
}
} else {
value = context.view[name];
}
if (value != null) {
break;
}
context = context.parent;
}
}
this._cache[name] = value;
}
if (typeof value === "function") {
value = value.call(this.view);
}
return value;
};
