这是我要做的：
>获取图像A和图像B.图像B是黑色和白色的蒙版图像.
>用图像B的红色通道替换图像A的Alpha通道.
>在画布上绘制图像C.
>在图像C的顶部绘制图像A.
一切似乎都可以直到第4步.图像C根本不可见,图像A应该是透明的,有白色.
cx.putImageData(imageA,0);
var resultData = cx.getImageData(0,view.width,view.height);
for (var h=0; h<resultData.data.length; h+=4) {
resultData.data[h+3] = imageB.data[h];
}
cx.putImageData(imageC,0);
cx.putImageData(resultData,0);
解决方法
Simon是对的：putImageData方法不注意合成;它只是复制像素值.为了获得合成,我们需要使用绘图操作.
我们需要将像素数据的通道(变成红色变成alpha),将变化的像素数据放入一个图像中,然后使用复合操作获得所需的掩码.
//copy from one channel to another
var assignChannel = function(imageData,channelTo,channelFrom) {
if(channelTo < 0 || channelTo > 3 || channelFrom < 0 || channelFrom > 3) {
throw new Error("bad channel number");
}
if(channelTo == channelFrom)
return;
var px = imageData.data;
for(var i = 0; i < px.length; i += 4) {
px[i + channelTo] = px[i + channelFrom];
}
};
/**============================================================================
* this function uses 3 or 4 canvases for clarity / pedagogical reasons:
* redCanvas has our mask image;
* maskCanvas will be used to store the alpha channel conversion of redCanvas' image;
* imageCanvas contains the image to be masked;
* ctx is the context of the canvas to which the masked image will be drawn.
============================================================================**/
var drawOnTopOfRed = function(redCanvas,maskCanvas,imageCanvas,ctx) {
var redImageData = redCanvas.getContext("2d").getImageData(0,w,h);
//assign the alpha channel
assignChannel(redImageData,3,0);
//write the mask image
maskCanvas.getContext("2d").putImageData(redImageData,0);
ctx.save();
//draw the mask
ctx.globalCompositeOperation = "copy";
ctx.drawImage(maskCanvas,0);
//draw the image to be masked,but only where both it
//and the mask are opaque; see http://www.whatwg.org/specs/web-apps/current-work/multipage/the-canvas-element.html#compositing for details.
ctx.globalCompositeOperation = "source-in";
ctx.drawImage(imageCanvas,0);
ctx.restore();
};
以涂鸦为例：
