我在我脑海中,试图第一次解析
JSON并处理多维数组.
{
"secret": "[Hidden]","minutes": 20,"link": "http:\/\/www.1.com","bookmark_collection": {
"free_link": {
"name": "#free_link#","bookmarks": [
{
"name": "1","link": "http:\/\/www.1.com"
},{
"name": "2","link": "http:\/\/2.dk"
},{
"name": "3","link": "http:\/\/www.3.in"
}
]
},"boarding_pass": {
"name": "Boarding Pass","link": "http:\/\/www.1.com\/"
},"link": "http:\/\/www.2.com\/"
},"link": "http:\/\/www.3.hk"
}
]
},"sublinks": {
"name": "sublinks","link": [
"http:\/\/www.1.com","http:\/\/www.2.com","http:\/\/www.3.com"
]
}
}
}
这分为3个部分,我的第一个维度上的静态数据(秘密,分钟,链接)我需要作为单独的字符串获取.
然后我需要一个没有固定名称的“书签集”字典,所以我需要它们的名称和每个书签的链接/名称.
然后是单独的子链接,它总是相同的,我需要单独的字典中的所有链接.
我正在阅读有关解析JSON的内容,但我找到的大部分内容都是一个放入1个字典的简单数组.
有没有人有任何好的技巧来做到这一点？
解决方法
在解析JSON之后,最终会得到一个Python dict.因此,假设上面的JSON位于名为input_data的字符串中：
import json
# This converts from JSON to a python dict
parsed_input = json.loads(input_data)
# Now,all of your static variables are referenceable as keys:
secret = parsed_input['secret']
minutes = parsed_input['minutes']
link = parsed_input['link']
# Plus,you can get your bookmark collection as:
bookmark_collection = parsed_input['bookmark_collection']
# Print a list of names of the bookmark collections...
print bookmark_collection.keys() # Note this contains sublinks,so remove it if needed
# Get the name of the Boarding Pass bookmark:
print bookmark_collection['boarding_pass']['name']
# Print out a list of all bookmark links as:
# Boarding Pass
# * 1: http://www.1.com/
# * 2: http://www.2.com/
# ...
for bookmark_definition in bookmark_collection.values():
# Skip sublinks...
if bookmark_definition['name'] == 'sublinks':
continue
print bookmark_definition['name']
for bookmark in bookmark_definition['bookmarks']:
print " * %(name)s: %(link)s" % bookmark
# Get the sublink definition:
sublinks = parsed_input['bookmark_collection']['sublinks']
# .. and print them
print sublinks['name']
for link in sublinks['link']:
print ' *',link
