这里发生了什么：
我希望“取消预订”按钮在点击后有一个超时.首次点击它会更改为显示“确认取消”按钮.几秒钟后,它返回“取消预订”.
我的控制台给了我：
@H_502_6@TypeError: $timeout is not a function我正在使用AngularJS $timeout：
控制器：
@H_502_6@'use strict'; module.controller('ReservationItemCtrl',['$scope','$stateParams','$RPC',function($scope,$stateParams,$RPC,$timeout) { ......other stuff....... ......other stuff....... $scope.toggleCancelReservation = function(reservation) { reservation.clickedcancel = true; $timeout(function(){reservation.clickedcancel = false},4000); }; } ]);模板：
@H_502_6@<button ng-show="!reservation.value.deleted && !deleted.value" class="btn btn-danger" ng-show="canCancel(reservation)" ng-if="!reservation.clickedcancel" ng-click="toggleCancelReservation(reservation)"> Cancel With Refund </button> <button type="button" class="btn btn-danger" ng-if="reservation.clickedcancel == true" ng-click="deleteReservation();" style="margin-top: -4px;"> Confirm Cancellation </button>我准确地在第一次点击时切换按钮然后再次点击它会正确取消/删除预订,但如果我在第一次点击后没有做任何事情,那么超时永远不会将其返回到原始按钮.在我的控制台中,我看到$timeout因某种原因不是函数？我把它包含在我的控制器中.我错过了什么吗？
解决方法
你忘了$timeout的内联表示法：
@H_502_6@'use strict';
module.controller('ReservationItemCtrl','$timeout',function ($scope,$timeout) {
......other stuff.......
......other stuff.......
$scope.toggleCancelReservation = function (reservation) {
reservation.clickedcancel = true;
$timeout(function () {
reservation.clickedcancel = false
},4000);
};
}
]);
