所以我使用PHP构建了一个向导,其中一个表单要求用户上传图像.
我已经构建了所有内容,唯一的问题是我必须能够在我的一个if语句中说,如果表单是使用jquery的submit()方法提交的.
var initUpload = function(){
$('.filebutton').change(function(e){
$("form").submit();
});
};
这就是我的if语句的样子.
if($this->input->post('back')){
//Tells me that the user clicked on the back button,and to go back 1 step in the wizard.
}else if(???){
//This is where I would like to say: if form was submitted with jquery.
}else{
//Else the user just clicked "next" and to continue normally.
}
我所知道的：
使用$this-> input-> post(‘back’)我可以使用值为BACK的按钮检查表单是否已提交.我已经var_dumped $this-> input-> post()但它只返回输入字段的值.
最佳答案
如上面的评论我被要求发表我的评论作为答案,所以你去
原文链接：https://www.f2er.com/jquery/428203.htmlif($this->input->post('back')){
//Tells me that the user clicked on the back button,and to go back 1 step in the wizard.
}else if($_FILES['your_image_filed_name']){
//This is where I would like to say: if form was submitted with jquery.
//you can use codeigniter's built in Upload libraray which v easy
}else{
//Else the user just clicked "next" and to continue normally.
}
$config_logo_image = array(
'allowed_types' => 'jpg|jpeg|gif|png','upload_path' => UPLOAD_PATH,//root path for image
'max_size' => 2000,);
$this->load->library('upload',$config_logo_image );
if($this->upload->do_upload('your_image_filed_name')){
$logo_image_data = $this->upload->data();
}
