我在我的asp.net控制器上使用下面的代码在javascript上返回我的Ajax上的Json对象
public JsonResult myMethod()
{
// return a Json Object,you could define a new class
return Json(new
{
Success = true,//error
Message = "Success" //return exception
});
}
jQuery的阿贾克斯：
$.ajax({
type: "POST",url: url_,data: search,success: function(data) {
//Show Json Properties from Controller ( If Success == false show exception Message from controller )
if (data.Success)
{
alert(data.Message); //display success
}
else
{
alert(data.Message) //display exception
}
},error: function(XMLHttpRequest,textStatus,errorThrown) {
alert("error: " + XMLHttpRequest.responseText);
},dataType: 'json'
});
如何在Web Api控制器上完成？
你能给我一些例子或网址作为参考。
感谢致敬
解决方法
如果你自己创建一个新的HttpContent类来提供JSON，比如……
public class JsonContent : HttpContent {
private readonly MemoryStream _Stream = new MemoryStream();
public JsonContent(object value) {
Headers.ContentType = new MediaTypeHeaderValue("application/json");
var jw = new JsonTextWriter( new StreamWriter(_Stream));
jw.Formatting = Formatting.Indented;
var serializer = new JsonSerializer();
serializer.Serialize(jw,value);
jw.Flush();
_Stream.Position = 0;
}
protected override Task SerializeToStreamAsync(Stream stream,TransportContext context) {
return _Stream.CopyToAsync(stream);
}
protected override bool TryComputeLength(out long length) {
length = _Stream.Length;
return true;
}
}
那你可以做到，
public HttpResponseMessage Get() {
return new HttpResponseMessage() {
Content = new JsonContent(new
{
Success = true,//error
Message = "Success" //return exception
})
};
}
就像你对JsonResult一样。
