Possible Duplicate:
07000
我有Apache2安装和Python工作.
我遇到了问题.我有两页.
一个是Python页面,另一个是带有JQuery的Html页面
我可以将Src改为google jquery链接.
有人可以告诉我如何让我的ajax帖子正常工作.
$(function()
{
alert('Im going to start processing');
$.ajax({
url: "saveList.py",type: "post",data: {'param':{"hello":"world"}},dataType: "application/json",success : function(response)
{
alert(response);
}
});
});
和Python代码
import sys
import json
def index(req):
result = {'success':'true','message':'The Command Completed Successfully'};
data = sys.stdin.read();
myjson = json.loads(data);
return str(myjson);
解决方法
这是一个示例html文件和附带的python CGI脚本,可以帮助您：
使用这个HTML：
<html>
<head>
<Meta http-equiv="content-type" content="text/html; charset=utf-8">
<title>test</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
<script>
$(function()
{
$('#clickme').click(function(){
alert('Im going to start processing');
$.ajax({
url: "/scripts/ajaxpost.py",datatype:"json",data: {'key':'value','key2':'value2'},success: function(response){
alert(response.message);
alert(response.keys);
}
});
});
});
</script>
</head>
<body>
<button id="clickme"> click me </button>
</body>
</html>
这个脚本：
#!/usr/bin/env python
import sys
import json
import cgi
fs = cgi.FieldStorage()
sys.stdout.write("Content-Type: application/json")
sys.stdout.write("\n")
sys.stdout.write("\n")
result = {}
result['success'] = True
result['message'] = "The command Completed Successfully"
result['keys'] = ",".join(fs.keys())
d = {}
for k in fs.keys():
d[k] = fs.getvalue(k)
result['data'] = d
sys.stdout.write(json.dumps(result,indent=1))
sys.stdout.write("\n")
sys.stdout.close()
单击按钮后,您可以看到cgi脚本返回：
{
"keys": "key2,key","message": "The command Completed Successfully","data": {
"key2": "value2","key": "value"
},"success": true
}
