这是我自制的序列化类：
public class JsonBuilder
{
private StringBuilder json;
public JsonBuilder()
{
json = new StringBuilder();
}
public JsonBuilder AddObjectType(string className)
{
json.Append("\"" + className + "\": {");
return this;
}
public JsonBuilder Add(string key,string val)
{
json.AppendFormat("\"{0}\":\"{1}\",",key,val);
return this;
}
public JsonBuilder Add(string key,int val)
{
json.AppendFormat("\"{0}\":{1},val);
return this;
}
public string Serialize()
{
return json.ToString().TrimEnd(new char[] { ',' }) + "}";
}
}
这是Web方法
[WebMethod]
public static string GetPersonInfo(string pFirstName,string pLastName)
{
var json = new JsonBuilder().AddObjectType("Person");
json.Add("FirstName","Psuedo" + pFirstName).Add("LastName","Tally-" + pLastName);
json.Add("Address","5035 Macleay Rd SE").Add("City","Salem");
json.Add("State","Oregon").Add("ZipCode","97317").Add("Age",99);
return json.Serialize();
}
Ajax调用客户端
$.ajax(
{
type: "POST",url: "Default.aspx/GetPersonInfo",data: JSON.stringify(name),contentType: "application/json; charset=uft-8",dataType: "json",success: function (rsp) { SetPerson(rsp); },error: function (rsp)
{
alert(rsp);
}
});
最后,我的回调方法
function SetPerson(rsp)
{
$('#fName').val(rsp.d.FirstName);
$('#lName').val(rsp.d.LastName);
$('#address').val(rsp.d.Address);
$('#city').val(rsp.d.City);
$('#state').val(rsp.d.State);
$('#zip').val(rsp.d.ZipCode);
SetPerson(rsp.d.Age);
}
rsp.d是一个包含所有属性的字符串……属性本身是未定义的.我知道我在这里缺少一些简单的东西.
从服务器返回的字符串
"Person": {"FirstName":"Psuedomatt","LastName":"Tally-cox","Address":"5035 Macleay Rd SE","City":"Salem","State":"Oregon","ZipCode":"97317","Age":99}
解决方法
您不应手动序列化返回值; ASP.NET将为您完成.尝试这样的事情：
[WebMethod]
public static Person GetPersonInfo(string pFirstName,string pLastName)
{
// Assuming you have a server-side Person class.
Person p = new Person();
p.FirstName = "Pseudo" + pFirstName;
p.LastName = "Tally-" + pLastName;
p.Address = "5035 Macleay Rd SE";
p.City = "Salem";
p.State = "Oregon";
p.ZipCode = "97317";
// ASP.NET will automatically JSON serialize this,if you call it with
// the correct client-side form (which you appear to be doing).
return p;
}
如果你需要返回更动态的东西,就像你的例子似乎正在做的那样,你可以使用匿名类型：
[WebMethod]
public static object GetPersonInfo(string pFirstName,string pLastName)
{
// ASP.NET will automatically JSON serialize this as well.
return new {
FirstName = "Pseudo" + pFirstName,LastName = "Tally-" + pLastName,Address = "5035 Macleay Rd SE",City = "Salem",State = "Oregon",ZipCode = "97317"
}
}
