jquery – 将表单数据转换为JSON对象

参见英文答案 > Convert form data to JavaScript object with jQuery51个
我试图将HTML表单数据转换为JSON对象,我有 this thread,但我不知道为什么它不适合我.我使用以下代码.

<form id="myform" action="" method="post">
    <div class="form-field">
        <label for="title">Title</label>
        <input name="title" id="title" type="text" value="" size="40" aria-required="true">
    </div>
    <div class="form-field form-required">
        <label for="your-name">Your Name</label>
        <input name="yourName" id="yourName" type="text" value="" size="40" aria-required="true">
    </div>
    <div class="form-field">
        <label for="contact-no">Contact No:</label>
        <input name="contact" id="contact" type="text" value="" size="40" aria-required="true">
    </div>
    <div class="form-field">
        <label for="description">Description:</label>
        <textarea name="description" id="description" rows="1" cols="40" aria-required="true"></textarea>
    </div>
    <div class="form-field">
        <label for="email">Email:</label>
        <input name="email" id="email" type="text" value="optional" size="40" aria-required="true">
    </div>
    <div class="form-field">
        <label for="city">City:</label>
        <input name="city" id="city" type="text" value="" size="40" aria-required="true">
    </div>
    <div class="form-field">
        <label for="country">Country:</label>
        <input name="country" id="country" type="text" value="" size="40" aria-required="true">
    </div>
    <div class="form-field">
        <label for="pic1">Picture 1:</label>
        <input type="file" name="pic1" id="pic1">
    </div>
    <div class="form-field">
        <label for="pic2">Picture 2:</label>
        <input type="file" name="pic2" id="pic2">
    </div>
    <div class="form-field">
        <label for="pic3">Picture 3:</label>
        <input type="file" name="pic3" id="pic3">
    </div>
    <div class="form-field">
        <label for="pic4">Picture 4:</label>
        <input type="file" name="pic4" id="pic4">
    </div>
    <div class="form-field">
        <label for="pic5">Picture 5:</label>
        <input type="file" name="pic5" id="pic5">
    </div>
    <div class="form-field">
        <label for="demand">Your Demand:</label>
        <input name="demand" id="demand" type="text" value="" size="40" aria-required="true">
    </div>
    <p class="submit">
        <input type="submit" name="postAd" id="postAd" class="button" value="Post Ad For Review">
    </p>
    <div id="results">hello</div>
</form>

$(document).ready(function(){
    $.fn.serializeObject = function() {
        var o = {};
        var a = this.serializeArray();
        $.each(a,function() {
            if (o[this.name] === undefined) {
                if (!o[this.name].push) {
                    o[this.name] = [o[this.name]];
                }
                o[this.name].push(this.value || '');
            } else {
                alert(this.name);
                o[this.name] = this.value || '';
            }
        });
        return o;
    };

    $('#myform').submit(function() {
        $('#result').text(JSON.stringify($('#myform').serializeObject()));
        return false;
    });
});

我试着调试它,我注意到当我的函数运行时,它总是在else语句中运行代码.

解决方法

我在JSFiddle中添加了上面的表单,它将JSON数据显示为输出.

Working JSFiddle

$(function() {
  $('form').submit(function() {
     $('#result').text(JSON.stringify($('form').serializeObject()));
    return false;
  });
});

jquery – 将表单数据转换为JSON对象

解决方法

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