<style>
    #Feedback { font-size: 1.4em; }
    #selectable .ui-selecting { background: #FECA40; }
    #selectable .ui-selected { background: #F39814; color: white; }
    #selectable { list-style-type: none; margin: 0; padding: 0; width: 60%; }
    #selectable li { margin: 3px; padding: 0.4em; font-size: 1.4em; height: 18px; }
    </style>
    <script>
    $(function() {
        $( "#selectable" ).selectable();
    });
    </script>



<div class="demo">

<ol id="selectable">
    <li class="ui-widget-content"><a href="">link can not click</a></li>
    <li class="ui-widget-content">Item 2</li>
    <li class="ui-widget-content">Item 3</li>
    <li class="ui-widget-content">Item 4</li>
    <li class="ui-widget-content">Item 5</li>
    <li class="ui-widget-content">Item 6</li>
    <li class="ui-widget-content">Item 7</li>
</ol>

</div><!-- End demo -->

似乎li内部的链接不再起作用.那么,我如何重新构造代码以使li可以被选中并且链接仍然可以同时使用？