这是我的代码
@H_301_2@jquery代码
$("input#shopName").autocomplete({
source: "getShop.PHP",minLength: 2
});
@H_301_2@从PHP返回的JSON值如下所示
if(isset($_GET["term"])){
$query=$_GET["term"];
$result = $dataset->get_custom_record("SELECT * FROM mc_shop WHERE shop_title like '%" . $query . "%' ORDER BY id");
}
while ($row = MysqL_fetch_array($result,MysqL_ASSOC)) {
$row_array['id'] = $row['id'];
$row_array['value'] =$row['shop_title'];
array_push($return_arr,$row_array);
}
echo json_encode($return_arr);
@H_301_2@自动完成工作正常,但在从自动完成中选择值时,我需要将相应的“id”值放在一个隐藏变量中,我不知道该怎么做>
解决方法
$("input#shopName").autocomplete({
source: "getShop.PHP",minLength: 2,select: function(event,ui) {
$("#theHidden").val(ui.item.id)
}
});
@H_301_2@见http://jqueryui.com/demos/autocomplete/#event-select
