是否有任何资源可以测试jQuery脚本/扩展/插件/版本兼容性问题?
解决方法
刚刚编写了一个小的jQuery插件来帮助解决版本兼容性问题…随意改进它.
(function($) { /** * Used for version test cases. * * @param {string} left A string containing the version that will become * the left hand operand. * @param {string} oper The comparison operator to test against. By * default,the "==" operator will be used. * @param {string} right A string containing the version that will * become the right hand operand. By default,the current jQuery * version will be used. * * @return {boolean} Returns the evaluation of the expression,either * true or false. */ $.isVersion = function(left,oper,right) { if (left) { var pre = /pre/i,replace = /[^\d]+/g,oper = oper || "==",right = right || $().jquery,l = left.replace(replace,''),r = right.replace(replace,l_len = l.length,r_len = r.length,l_pre = pre.test(left),r_pre = pre.test(right); l = (r_len > l_len ? parseInt(l) * ((r_len - l_len) * 10) : parseInt(l)); r = (l_len > r_len ? parseInt(r) * ((l_len - r_len) * 10) : parseInt(r)); switch(oper) { case "==": { return (true === (l == r && (l_pre == r_pre))); } case ">=": { return (true === (l >= r && (!l_pre || l_pre == r_pre))); } case "<=": { return (true === (l <= r && (!r_pre || r_pre == l_pre))); } case ">": { return (true === (l > r || (l == r && r_pre))); } case "<": { return (true === (l < r || (l == r && l_pre))); } } } return false; } })(jQuery);
可以像这样使用:
$.isVersion("1.4.2"); // returns true,if $().jquery == "1.4.2" $.isVersion("1.3.2",">"); // returns true if $().jquery > "1.3.2" $.isVersion("1.3",">","1.2.6"); // returns true $.isVersion("1.3.2","<","1.3.1"); // returns false $.isVersion("1.4.0",">=","1.3.2"); // returns true $.isVersion("1.4.1","<=","1.4.1"); // returns true
还支持预发布(版本比预版本重,因此1.4.0pre <1.4.0):
$.isVersion("1.4.2","1.4.2pre"); // returns false