我有这个html / css代码：
<body>
<!-- BEGIN: HEADER AREA -->
<?PHP require("snippets/header_area.PHP"); ?>
<!-- END: HEADER AREA -->
<div id = "presentation_area">
<div id = "submenu_area">
<div id = "sliding_menu_area">
</div>
<div id = "tags">
<div id = "1">
<img src = "lang/el/images/1.png" />
</div>
<div id = "2">
<img src = "lang/el/images/2.png" />
</div>
<div id = "3">
<img src = "lang/el/images/3.png" />
</div>
<div id = "4">
<img src = "lang/el/images/4.png" />
</div>
</div>
</div>
</div>
</body>
当用户点击除#sub_menu_area之外的所有其他内容时,我试图触发一个函数.我使用js的以下部分：
$('*').not('#submenu_area').click(function(){
if(slide == "open"){
$('#sliding_menu_area').toggle(effect);
slide = "close";
}
});
不幸的是,孩子们不知何故不被排除在外,并且点击它会翻转很多次.有谁知道如何正确地做到这一点？！ 原文链接：https://www.f2er.com/jquery/177713.html
