我试图使用grep过滤json对象数组,以便搜索数组,如果任何键#2-6的值为yes,则返回键1和7的值.
数组在下面 – 换句话说,如果’location’键的任何值为yes,则名称和描述将作为列表项返回.
很感谢任何形式的帮助.
[
{
"name": "name","location1": "no","location2": "no","location3": "yes","location4": "no","location5": "no","description": "description of services"
},{
"name": "name","location1": "yes","description": "description of services"
}
]
解决方法
您需要同时使用grep和map.如果a是上面描述的数组(但是有name1,name2等),那么在以下之后：
var b = $.grep(a,function(el,i) {
return el.location1.toLowerCase() === "yes"
|| el.location2.toLowerCase() === "yes"
|| el.location3.toLowerCase() === "yes"
|| el.location4.toLowerCase() === "yes"
|| el.location5.toLowerCase() === "yes";
});
var c = $.map(b,i) {
return {
name: el.name,description: el.description
};
});
c将包含[{“name”：“name1”,“description”：“services1”的描述},{“name”：“name2”,“description”：“services2的描述”}]
