有表tb,数据如下
A1 A2 A3 A4 A5
1 2 5 3 4
2 2 3 4 5
0 3 4 2 5
如何输出
A1 A2 A3 A4 A5 最大 最小 5以上个数
1 2 5 3 4 5 1 1
2 2 3 4 5 5 2 1
0 3 5 2 6 6 0 2
答:
sql Server的聚合函数是在列上的,所以可以写自定义的函数,也可以想办法把列变为行,再用聚合函数处理
解决示例
--测试数据
DECLARE @t TABLE(A1 int,A2 int,A3 int,A4 int,A5 int)
INSERT @t SELECT 1,2,5,3,4
UNION ALL SELECT 2,4,5
UNION ALL SELECT 0,5
--查询
SELECT *,
[min] = (
SELECT MIN(v) FROM(
SELECT v=A.A1 UNION SELECT v=A.A2 UNION SELECT v=A.A3
UNION SELECT v=A.A4 UNION SELECT v=A.A5
)B),
[max] = (
SELECT MAX(v) FROM(
SELECT v=A.A1 UNION SELECT v=A.A2 UNION SELECT v=A.A3
UNION SELECT v=A.A4 UNION SELECT v=A.A5
)B),
[count>=5] = (
SELECT COUNT(*) FROM(
SELECT v=A.A1 UNION SELECT v=A.A2 UNION SELECT v=A.A3
UNION SELECT v=A.A4 UNION SELECT v=A.A5
)B WHERE v>=5)
FROM @t A
查询结果:
A1 A2 A3 A4 A5 min max count>=5
----------- ----------- ----------- ----------- ----------- ----------- -----------
1 2 5 3 4 1 5 1
2 2 3 4 5 2 5 1
0 3 4 2 5 0 5 1