单向列表倒置:
算法示例:
head end tmp
1---->2---->3---->4---->5
end head tmp
2---->1 3---->4---->5
head end tmp
2---->1 3---->4---->5
end head tmp
3---->2---->1 4---->5
head end tmp
3---->2---->1 4---->5
end head tmp
4---->3---->2---->1 5
head end tmp
4---->3---->2---->1 5 NULL
end head
5---->4---->3---->2---->1
示例代码:
#include <stdio.h> #include <stdlib.h> typedef struct LIST_NODE { struct LIST_NODE* next; int value; }LIST_NODE; LIST_NODE* list_inversion(LIST_NODE *head) { printf("in list_inversion\n"); LIST_NODE *tmp,*end; end = head->next; tmp = end->next; head->next = NULL; while (NULL != tmp) { end->next = head; head = end; end = tmp; tmp = tmp->next; } end->next = head; return end; } int main() { LIST_NODE *head,*end; head = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1); end = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1); LIST_NODE* tmp = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1); int len = 0,value = 0; printf("Input length of list :\n"); scanf("%d",&len); tmp = head; for(int i= 0; i < len; i++) { LIST_NODE* tmp2 = (LIST_NODE*)malloc(sizeof(LIST_NODE)*1); printf("Input the current value : "); tmp->next = tmp2; if (i == len-1) { tmp->next = NULL; } scanf("%d",&value); tmp->value = value; tmp = tmp->next; } LIST_NODE *aList = list_inversion(head); printf("new list : \n"); while (NULL != aList) { printf("%d\n",aList->value); aList= aList->next; } }
示例运行结果:
[root@localhost List]# ./listtest Input length of list : 5 Input the current value : 1 Input the current value : 2 Input the current value : 3 Input the current value : 4 Input the current value : 5 in list_inversion new list : 5 4 3 2 1
原文链接:https://www.f2er.com/javaschema/286527.html