CIDR前缀聚合表

前端之家收集整理的这篇文章主要介绍了CIDR前缀聚合表前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。

CIDR的另一个好处就是可以进行前缀路由聚合。例如, 16个原来的C类(/24)网络现在可以聚合在一起,对外显示了一个/20的网络了(如果这些网络的的地址前20位都相同,见下红字部分)。两个对齐的/20网络又可进一步聚合为/19,依此类推。这有效地减少了要对外显示的网络数,防止了'路由表爆炸',也遏制了互联网进一步扩大。

CIDR
IP/CIDR Δ 与最后一个地址的差值 掩码 主机数 (*) 类别 备注
a.b.c.d/32 +0.0.0.0 255.255.255.255 1 1/256 C
a.b.c.d/31 +0.0.0.1 255.255.255.254 2 1/128 C d = 0 ... (2n) ... 254
a.b.c.d/30 +0.0.0.3 255.255.255.252 4 1/64 C d = 0 ... (4n) ... 252
a.b.c.d/29 +0.0.0.7 255.255.255.248 8 1/32 C d = 0 ... (8n) ... 248
a.b.c.d/28 +0.0.0.15 255.255.255.240 16 1/16 C d = 0 ... (16n) ... 240
a.b.c.d/27 +0.0.0.31 255.255.255.224 32 1/8 C d = 0 ... (32n) ... 224
a.b.c.d/26 +0.0.0.63 255.255.255.192 64 1/4 C d = 0,64,128,192
a.b.c.d/25 +0.0.0.127 255.255.255.128 128 1/2 C a.b.c.0/24 +0.0.0.255 255.255.255.000 256 1 C a.b.c.0/23 +0.0.1.255 255.255.254.000 512 2 C c = 0 ... (2n) ... 254
a.b.c.0/22 +0.0.3.255 255.255.252.000 1,024 4 C c = 0 ... (4n) ... 252
a.b.c.0/21 +0.0.7.255 255.255.248.000 2,048 8 C c = 0 ... (8n) ... 248
a.b.c.0/20 +0.0.15.255 255.255.240.000 4,096 16 C c = 0 ... (16n) ... 240
a.b.c.0/19 +0.0.31.255 255.255.224.000 8,192 32 C c = 0 ... (32n) ... 224
a.b.c.0/18 +0.0.63.255 255.255.192.000 16,384 64 C c = 0,170); padding:0.2em 0.4em">a.b.c.0/17 +0.0.127.255 255.255.128.000 32,768 128 C a.b.0.0/16 +0.0.255.255 255.255.000.000 65,536 256 C = 1 B a.b.0.0/15 +0.1.255.255 255.254.000.000 131,072 2 B b = 0 ... (2n) ... 254
a.b.0.0/14 +0.3.255.255 255.252.000.000 262,144 4 B b = 0 ... (4n) ... 252
a.b.0.0/13 +0.7.255.255 255.248.000.000 524,288 8 B b = 0 ... (8n) ... 248
a.b.0.0/12 +0.15.255.255 255.240.000.000 16 B b = 0 ... (16n) ... 240
a.b.0.0/11 +0.31.255.255 255.224.000.000 32 B b = 0 ... (32n) ... 224
a.b.0.0/10 +0.63.255.255 255.192.000.000 4,194,304 64 B b = 0,170); padding:0.2em 0.4em">a.b.0.0/9 +0.127.255.255 255.128.000.000 128 B a.0.0.0/8 +0.255.255.255 255.000.000.000 256 B = 1 A a.0.0.0/7 +1.255.255.255 254.000.000.000 33,554,432 2 A a = 0 ... (2n) ... 254
a.0.0.0/6 +3.255.255.255 252.000.000.000 67,108,864 4 A a = 0 ... (4n) ... 252
a.0.0.0/5 +7.255.255.255 248.000.000.000 134,217,728 8 A a = 0 ... (8n) ... 248
a.0.0.0/4 +15.255.255.255 240.000.000.000 268,435,456 16 A a = 0 ... (16n) ... 240
a.0.0.0/3 +31.255.255.255 224.000.000.000 536,870,912 32 A a = 0 ... (32n) ... 224
a.0.0.0/2 +63.255.255.255 192.000.000.000 64 A a = 0,170); padding:0.2em 0.4em">a.0.0.0/1 +127.255.255.255 128.000.000.000 128 A 0.0.0.0/0 +255.255.255.255 000.000.000.000 256 A

原文链接:https://www.f2er.com/javaschema/284032.html

猜你在找的设计模式相关文章