依赖注入 – Castle Windsor传递构造函数参数

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我有一个具有几个属性的IAddress类。然后我有一个实现这个接口的具体类型。这个具体类型有一些我可以使用的不同的构造函数。如何在运行时将参数值传递给其中一个构造函数?我不能使用配置文件,因为我将重复使用这个具体类型多次,每次参数值将不同。
IWindsorContainer container = new WindsorContainer(new XmlInterpreter());
IAddress address = container.Resolve<IAddress>();


public interface IAddress
{
    string Address1 { get; set; }
    string Address2 { get; set; }
    string City { get; set; }
    string State { get; set; }
    string ZipCode { get; set; }
}


class TestAddress : IAddress
{

    private string _address1;
    private string _address2;
    private string _city;
    private string _countyName;
    private string _state;
    private string _zipCode;

    public string Address1
    {
        get { return _address1; }
        set { _address1 = value; }
    }

    public string Address2
    {
        get { return _address2; }
        set { _address2 = value; }
    }

    public string City
    {
        get { return _city; }
        set { _city = value; }
    }

    public string State
    {
        get { return _state; }
        set { _state = value; }
    }

    public string ZipCode
    {
        get { return _zipCode; }
        set { _zipCode = value; }
    }

    public string CountyName
    {
        get { return _countyName; }
        set { _countyName = value; }
    }


    public MelissaAddress(string address1,string address2,string city,string state,string zipcode)
    {
        Address1 = address1;
        Address2 = address2;
        City = city;
        State = state;
        ZipCode = zipcode;
    }

    public MelissaAddress(string address1,string zipcode) : this(address1,address2,null,zipcode)
    { }

    public MelissaAddress(string address1,string state) : this(address1,city,state,null)
    { }
}
您可以使用Resolve(对象参数AsAnonymousType)或Resolve(IDictionary参数)。 Windsor将选择最匹配的构造函数

例如,这将选择您的第二个构造函数

container.Resolve<IAddress>(
    new {address1 = "myaddress1",address2 = "myaddress2",zipcode = "myzipcode"}
)

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