假设我得到以下结构：
<div id="le-main-id" class="le-main-class"> <div id="le-main-id1" class="le-main-class1"></div> <div id="le-main-id2" class="le-main-class2"></div> <div id="le-main-id3" class="le-main-class3"></div> </div>
我需要隐藏所有内容,除了div编号2(id =“le-main-id2”class =“le-main-class2”),但是我不能只使用display：none,因为在我的真实代码我得到了40个div来隐藏,所以它可能需要太长时间才会结束.
所以我怎么能隐藏除第二个div之外的所有东西？
像这样的东西
#le-main-id.le-main-class2 { /* visible:yes; all the others: no; */}
#le-main-id { /* visible:no; */}
更新：
我按照答案,但它不起作用.这是我正在尝试的方式：
#lehometemplates > :not (.wpbdp-field-title) {
display: none !important;
}
更新2：
我相信我没有100％提出这个问题,即使目前的答案确实有帮助.让我说清楚一下：
假设这就是我所拥有的：
<div id="le-main-id" class="le-main-class">
<div id="1" class="1">
<div id="2" class="2">
<div id="3" class="3">
<div id="4" class="4">
<div id="le-main-id1" class="le-main-class1">
<div id="le-main-id1" class="le-main-class1"></div>
<div id="le-main-id2" class="le-main-class2"></div>
<div id="le-main-id3" class="le-main-class3"></div>
</div>
</div>
</div>
</div>
</div>
</div>
所以要隐藏所有内容并保持div class =“le-main-class2”我将使用类似……
#le-main-id > :not (.le-main-class2) {
display: none !important;
}
这样对吗？
看,我只是不想首先选择每个父div,如果可能的话.
最后更新
最后成功了,如果我有以下代码：
<div id="le-main-id" class="le-main-class">
<div id="1" class="1">
<div id="2" class="2">
<div id="3" class="3">
<div id="4" class="4">
<div id="le-main-id111" class="le-main-class111">
<div id="le-main-id1" class="le-main-class1"></div>
<div id="le-main-id2" class="le-main-class2"></div>
<div id="le-main-id3" class="le-main-class3"></div>
</div>
</div>
</div>
</div>
</div>
</div>
那我所要做的就是：
.le-main-class .le-main-class111 > :not(.le-main-class2) {
display: none;
}
这样我就会隐藏.le-main-class和.le-main-class111的每个子节点,除了.le-main-class2.
解决方法
你可以使用
:not()伪类：
#le-main-id > :not(.le-main-class2) { display: none; }
值得注意的是：不是()is supported in IE9+.
对于旧版Web浏览器,您可以隐藏所有子项< div> s,然后覆盖特定项的声明.
#le-main-id > div { display: none; }
#le-main-id > .le-main-class2 { display: block; }
更新
根据new update,实际标记比之前发布的标记更复杂.
由于嵌套元素可能包含其他内容,因此除了.le-main-class2之外,隐藏#le-main-id内部所有内容的一种正确方法是将visibility: hidden添加到主容器中并将其重新设置为.le-main上的可见内容-class2.
但是,visibility离开了被占领的空间.但是我们可以通过在主容器中添加line-height：0并在.le-main-class2上将值重新设置为1.2来解决这个问题.
* { margin: 0; /* just for demo */ }
#le-main-id {
visibility: hidden;
line-height: 0;
background-color: gold;
}
#le-main-id img {
display: none; /* to hide the images */
}
#le-main-id .le-main-class2 {
visibility: visible;
line-height: 1.2;
background-color: orange;
}
<div id="le-main-id" class="le-main-class">
.le-main-class
<div id="1" class="1"> id="1" class="1"
<div id="2" class="2"> id="2" class="2"
<div id="3" class="3"> id="3" class="3"
<div id="4" class="4"> id="4" class="4"
<img src="http://placehold.it/100" alt="">
<div id="le-main-id1" class="le-main-class1">
.le-main-class1
<div id="le-main-id1" class="le-main-class1">.le-main-class1</div>
<div id="le-main-id2" class="le-main-class2">.le-main-class2</div>
<div id="le-main-id3" class="le-main-class3">.le-main-class3</div>
</div>
</div>
</div>
</div>
</div>
</div>
<p>
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