我有一个Web Api方法，它应该返回一个xml数据，但它返回字符串：
public class HealthCheckController : ApiController
{
[HttpGet]
public string Index()
{
var healthCheckReport = new HealthCheckReport();
return healthCheckReport.ToXml();
}
}
它返回：
<string xmlns="http://schemas.microsoft.com/2003/10/Serialization/"> <myroot><mynode></mynode></myroot> </string>
我已经添加了这个映射：
config.Routes.MapHttpRoute(
name: "HealthCheck",routeTemplate: "healthcheck",defaults: new
{
controller = "HealthCheck",action = "Index"
});
如何使它只返回xml位：
<myroot><mynode></mynode></myroot>
如果我只是使用MVC，我可以使用以下，但Web API不支持“内容”：
[HttpGet]
public ActionResult Index()
{
var healthCheckReport = new HealthCheckReport();
return Content(healthCheckReport.ToXml(),"text/xml");
}
config.Formatters.Remove(config.Formatters.JsonFormatter); config.Formatters.XmlFormatter.UseXmlSerializer = true;
解决方法
最快的方式是这样，
public class HealthCheckController : ApiController
{
[HttpGet]
public HttpResponseMessage Index()
{
var healthCheckReport = new HealthCheckReport();
return new HttpResponseMessage() {Content = new StringContent( healthCheckReport.ToXml(),Encoding.UTF8,"application/xml" )};
}
}
但是也很容易构建一个从HttpContent派生出来直接支持XmlDocument或XDocument的新的XmlContent类。例如
public class XmlContent : HttpContent
{
private readonly MemoryStream _Stream = new MemoryStream();
public XmlContent(XmlDocument document) {
document.Save(_Stream);
_Stream.Position = 0;
Headers.ContentType = new MediaTypeHeaderValue("application/xml");
}
protected override Task SerializeToStreamAsync(Stream stream,System.Net.TransportContext context) {
_Stream.CopyTo(stream);
var tcs = new TaskCompletionSource<object>();
tcs.SetResult(null);
return tcs.Task;
}
protected override bool TryComputeLength(out long length) {
length = _Stream.Length;
return true;
}
}
您可以像使用StreamContent或StringContent一样使用它，除了它接受XmlDocument，
public class HealthCheckController : ApiController
{
[HttpGet]
public HttpResponseMessage Index()
{
var healthCheckReport = new HealthCheckReport();
return new HttpResponseMessage() {
RequestMessage = Request,Content = new XmlContent(healthCheckReport.ToXmlDocument()) };
}
}
