我做了一个简单的项目,使用ksoap2调用wcf Web服务.但是当它调用envelope.getResponse();它给出了错误的说法
错误：
SoapFault – faultcode：’a：InternalServiceFault’faultstring：’由于内部错误,服务器无法处理请求.有关错误的更多信息,请在服务器上启用IncludeExceptionDetailInFaults(来自ServiceBehaviorAttribute或配置行为)以将异常信息发送回客户端,或者根据Microsoft .NET Framework 3.0 SDK文档启用跟踪并检查服务器跟踪日志. faultactor：’null’detail：null
package testing.wcf;
import java.io.IOException;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParserException;
import org.xmlpull.v1.XmlSerializer;
import android.os.Bundle;
import android.os.StrictMode;
import android.widget.TextView;
import android.annotation.SuppressLint;
import android.app.Activity;
public class MainActivity extends Activity
{
private static final String strNAMESPACE = "http://www.testing.co.in/TestingService/";
private static final String strURL = "http://www.testing.co.in/TestingService/UserDetails.svc";
private static final String strSOAP_ACTION = "http://testing.co.in/TestingService/UserDetails/LoginDetails";
private static final String strMETHOD_NAME = "LoginDetails";
TextView tv;
StringBuilder sb;
String strInputXML;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv = (TextView)findViewById(R.id.testing);
sb = new StringBuilder();
Call();
tv.setText(sb.toString());
//setContentView(tv);
}
public void Call()
{
try
{
SoapObject request = new SoapObject(strNAMESPACE,strMETHOD_NAME);
String inputxml = "<?xml version="+"\""+"1.0"+"\""+" encoding="+"\""+"utf-8"+"\""+" ?>" +"<MOB> \n <PIN>0000</PIN> \n <LOGINID>TEST</LOGINID> \n <PNUMBER>112233</pNUMBER> \n <REQUESTID>LoginVal</REQUESTID> \n </MOB>";
request.addAttribute("strInputXML",inputxml);
request.addAttribute("strOutputXML","");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(strURL);
androidHttpTransport.call(strSOAP_ACTION,envelope);
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
String resultData = result.toString();
sb.append(resultData + "\n");
}
catch(Exception e)
{
sb.append("Error:\n" + e.getMessage() + "\n");
}
}
}
在这里,我想发送这样的请求
<?xml version="1.0" encoding="utf-8" ?> <PhoneData> <PINNO>0000</PINNO> <LOGINID>HELLO</LOGINID> <PASSWORD>1234</PASSWORD> <REQID>0</REQID> </PhoneData>
我的回应应该是XML
<?xml version="1.0" encoding="utf-8" ?> <PhoneData> <OTA>1234</OTA> </PhoneData>
解决方法
我发布我的工作代码以消耗WCF(WCF的绑定必须是basicHttpBinding！)：
private static final String NAMESPACE = "http://tempuri.org/";
private static String URL="your url";
private static final String SOAP_ACTION_VALIDATION = "IValidateUser_wcf/ValidateUser";
private static final String VALIDATION_METHOD = "ValidateUser";
public boolean validateUser_WCF(String username,String password){
SoapSerializationEnvelope envelope = null;
SoapObject request = null;
HttpTransportSE httpTransportSE = null;
try {
request = new SoapObject(NAMESPACE,VALIDATION_METHOD);
request.addProperty("username",username);
request.addProperty("password",password);
envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
//////////////////////////////
// here you can add a HEADER element if you want
Element[] header = new Element[1];
header[0] = new Element().createElement(NAMESPACE_INFOCAD,"a1");
header[0].addChild(Node.TEXT,"HeaderTextContent");
envelope.headerOut = header;
//////////////////////////////
httpTransportSE = new HttpTransportSE(URL+VALIDATION_URI,10*10000); // second parameter is timeout
httpTransportSE.debug = true;
httpTransportSE.setXmlVersionTag("<?xml version=\"1.0\" encoding=\"utf-8\"?>");
httpTransportSE.call(NAMESPACE+SOAP_ACTION_VALIDATION,envelope);
// if response is a simple text result,you can call SoapPrimitive,if not,you have to call SoapObject result and navigate in response's tree like an xml file
SoapPrimitive result = (SoapPrimitive)envelope.getResponse();
//To get the data.
String textResult = result.toString();
Log.i("textResult",textResult);
return true;
} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}finally{
// here you can see in LOG what is request you send and what is response received
Log.i(getClass().getSimpleName(),"requestDump : "+httpTransportSE.requestDump);
Log.i(getClass().getSimpleName(),"responseDump : "+httpTransportSE.responseDump);
}
return false;
}
希望我的代码可以帮助你:).它的工作率为100％
