如果事实证明ajax是前进的唯一方法,那么我需要知道什么来调用一个PHP文件来创建一个按钮按下的文本文件?我正在为自己创建一个简单的博客网站,我已经获得了该网站的代码和javascript,可以将我在textarea中写的帖子立即显示出来.我只想将它链接到一个PHP文件,该文件将在服务器上创建永久博客帖子,这样当我重新加载页面时,帖子仍然存在.
感谢您抽出宝贵时间阅读和回答.
解决方法
I don’t care if the page reloads or displays the results immediately;
好!
注意:如果您不想刷新页面,请参阅“Ok …但是如何使用Ajax?”下面.
I just want to have a button on my website make a PHP file run.
这可以通过一个带有单个按钮的表单来完成:
<form action=""> <input type="submit" value="my button"/> </form>
That’s it.
差不多.另请注意,有些情况下ajax确实是要走的路.
这取决于你想要什么.一般而言,当您想要避免重写页面时,您只需要ajax.你还说你不关心那个.
If I can write the code inside HTML just fine,why can’t I just reference the file for it in there or make a simple call for it in Javascript?
因为PHP代码不在HTML中就好了.这是大多数服务器端脚本语言工作方式(包括PHP,JSP和ASP)的错觉.该代码仅存在于服务器上,并且在没有某种远程调用的情况下,客户端(浏览器)无法访问该代码.
如果您要求浏览器显示页面的源代码,您可以看到此证据.那里你不会看到PHP代码,因为PHP代码没有发送到客户端,因此无法从客户端执行.这就是为什么你需要做一个远程调用才能让客户端触发PHP代码的执行.
如果您不使用表单(如上所示),您可以使用一个名为Ajax的小东西从JavaScript进行远程调用.您可能还想考虑是否可以直接在JavaScript中完成PHP中的操作.
<form action="myPHPfile.PHP"> <input type="submit" value="click on me!"> </form>
用户将最终进入myPHPfile.PHP页面.要使其适用于当前页面,请将action设置为空字符串(这是我在早期给出的示例中所做的).
I just want to link it to a PHP file that will create the permanent blog post on the server so that when I reload the page,the post is still there.
你想在服务器上进行操作,你应该让你的表单有你需要的字段(即使type =“hidden”并使用POST):
<form action="" method="POST"> <input type="text" value="default value,you can edit it" name="myfield"> <input type="submit" value = "post"> </form>
What do I need to know about it to call a PHP file that will create a text file on a button press?
见:How to write into a file in PHP.
你如何从服务器上的POST接收数据?
我很高兴你问…因为你是一个新手,我会给你一个你可以遵循的模板:
<?PHP if ($_SERVER['REQUEST_METHOD'] === 'POST') { //Ok we got a POST,probably from a FORM,read from $_POST. var_dump($_PSOT); //Use this to see what info we got! } else { //You could assume you got a GET var_dump($_GET); //Use this to see what info we got! } ?> <!DOCTYPE html> <html lang="en"> <head> <Meta char-set="utf-8"> <title>Page title</title> </head> <body> <form action="" method="POST"> <input type="text" value="default value,you can edit it" name="myfield"> <input type="submit" value = "post"> </form> </body> </html>
注意:您可以删除var_dump,它仅用于调试目的.
我如何…
我知道下一阶段,你会问如何:
>如何将变量从PHP文件传递到另一个?
>如何记住用户/登录?
>如何避免重新加载页面时出现的恼人信息?
对此有一个答案:会话.
我将为Post-Redirect-Get提供更广泛的模板
<?PHP if ($_SERVER['REQUEST_METHOD'] === 'POST') { var_dump($_PSOT); //Do stuff... //Write results to session session_start(); $_SESSION['stuff'] = $something; //You can store stuff such as the user ID,so you can remeember him. //redirect: header('Location: ',true,303); //The redirection will cause the browser to request with GET //The results of the operation are in the session variable //It has empty location because we are redirecting to the same page //Otherwise use `header('Location: anotherpage.PHP',303);` exit(); } else { //You could assume you got a GET var_dump($_GET); //Use this to see what info we got! //Get stuff from session session_start(); if (array_key_exists('stuff',$_SESSION)) { $something = $_SESSION['stuff']; //we got stuff //later use present the results of the operation to the user. } //clear stuff from session: unset($_SESSION['stuff']); //set headers header('Content-Type: text/html; charset=utf-8'); //This header is telling the browser what are we sending. //And it says we are sending HTML in UTF-8 encoding } ?> <!DOCTYPE html> <html lang="en"> <head> <Meta char-set="utf-8"> <title>Page title</title> </head> <body> <?PHP if (isset($something)){ echo '<span>'.$something.'</span>'}?>; <form action="" method="POST"> <input type="text" value="default value,you can edit it" name="myfield"> <input type="submit" value = "post"> </form> </body> </html>
请查看PHP.net,了解您无法识别的任何函数调用.另外 – 如果你还没有 – 获得关于HTML5的好教程.
另外,使用UTF-8 because UTF-8!
笔记:
I’m making a simple blog site for myself and I’ve got the code for the site and the javascript that can take the post I write in a textarea and display it immediately.
如果您使用的是CMS(Codepress,Joomla,Drupal等)?这使你对如何做事情产生了一些限制.
此外,如果您正在使用框架,您应该查看他们的文档或在他们的论坛/邮件列表/讨论页面/联系人询问或尝试询问作者.
好的……但是我怎么使用Ajax呢?
嗯……一些JavaScript库让Ajax变得简单.既然你是初学者,我会推荐jQuery.
所以,让我们通过Ajax使用jQuery向服务器发送一些东西,我将使用$.post代替$.ajax这个例子.
<?PHP if ($_SERVER['REQUEST_METHOD'] === 'POST') { var_dump($_PSOT); header('Location: ',303); exit(); } else { var_dump($_GET); header('Content-Type: text/html; charset=utf-8'); } ?> <!DOCTYPE html> <html lang="en"> <head> <Meta char-set="utf-8"> <title>Page title</title> <script> function ajaxmagic() { $.post( //call the server "test.PHP",//At this url { field: "value",name: "John" } //And send this data to it ).done( //And when it's done function(data) { $('#fromAjax').html(data); //Update here with the response } ); } </script> </head> <body> <input type="button" value = "use ajax",onclick="ajaxmagic()"> <span id="fromAjax"></span> </body> </html>
注意:如果需要,您可以将会话与ajax和东西混合在一起.
我如何…
> How do I connect to the database?
> How do I prevent SQL injection?
> Why shouldn’t I use Mysql_* functions?
…对于这些或任何其他,请提出另一个问题.这对于这个来说太过分了.